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crimeas [40]
3 years ago
13

A flower garden has a length of 10.5 feet and a width of 4.4 feet.

Mathematics
1 answer:
Sav [38]3 years ago
3 0

Answer:

B. 46.2

Step-by-step explanation:

A=L*W

So, Area (A) would be 10.5 X 4.4 which would equal 46.2 sq. feet.

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Which expression is equivalent to −2.1+(−5.9)+(−3.7) ?
notka56 [123]

Answer:

The last one, −2.1−(5.9+3.7)

Step-by-step explanation:

−2.1+(−5.9)+(−3.7) = -2.1-5.9-3.7 = -11.7

the only expression that will come out as -11.7 is the last one

8 0
3 years ago
Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin
ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let \mu = <em><u>mean duration of 15-sided union rugby games after the meeting.</u></em>

So, Null Hypothesis, H_0 : \mu \geq 185 minutes      {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, H_A : \mu < 185 minutes     {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean duration of 15-sided union rugby games = 179 min

            s = sample standard deviation = 12 minutes

            n = sample of 15-sided rugby games = 36

So, <u><em>the test statistics</em></u>  =  \frac{179-185}{\frac{12}{\sqrt{36} } }  ~ t_3_5

                                       =  -3

The value of t test statistics is -3.

<u>Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0
3 years ago
Please help! I will give 50 points and brainliest.
QveST [7]

Answer:

Step-by-step explanation:

f * g = (x^2 + 3x - 4) (x+4)

open bracket

x((x^2 + 3x - 4) + 4 (x^2 + 3x - 4)

x³ +3x²-4x+x²+12x-16

x³+3x²+x²-4x+12x-16

x³+4x²+8x-16 (domain is all real numbers.

f/g = (x^2 + 3x - 4)/(x+4)

factorising (x^2 + 3x - 4)

x²+4x-x_4

x(x+4) -1 (x+4)

(x+4)(x-1)

f/g = (x^2 + 3x - 4)/(x+4) =(x+4)(x-1)/(x+4) = (x-1)

Before factorisation, this was a rational function so the domain is all real numbers excluding any value that would make the denominator equal zero.

Hence I got x - 1, and x cannot equal -4

 So the domain is just all real numbers without -4

8 0
3 years ago
What is the sum of 3+(-5)?
pantera1 [17]

Answer:

Your answer is -2 hope this helps

7 0
3 years ago
Read 2 more answers
A car weighs 2332 pounds. If 372 pounds of old parts are removed and replaced with 412 pounds of new parts, find new weights of
Makovka662 [10]

Answer:

2372

Step-by-step explanation:

You would do the equation 2332-372+412

5 0
3 years ago
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