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3 years ago

How many real solutions does a quadratic equation have if it's discrimination is zero

2 answers:

7 0

, there can be 0 , 1 , or 2 solutions<span> to a quadratic equation, depending on whether the expression inside the square root sign, (b </span>2<span> - 4ac) , is positive, negative, or zero</span>

slava [35]3 years ago

5 0

Here is an easy way to remember, If the discriminant is equal to zero there will be one solution, if the discriminant is less than 0 or negative there are no real solutions, more than 0 or positive there will be two. So one real solution if it is equal

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At a clearance sale,Jill got 70% off a silver bracelet.If she paid the cashier $27 ,what was the original price of the bracelet

mart [117]

Answer:

$38.57

Step-by-step explanation:

Make a proportion.

$\frac{27}{x} = \frac{70}{100}$

Cross multiply.

27 times 100 = 2700

2700 divided by 70 = 38.57142857

Round the result to the hundredths place.

38.57142857 ≈ 38.57

**Hope this helps!

4 0

3 years ago

A florist received 30 dozen roses. She order 20 dozen. What percent did she receive in excess

KonstantinChe [14]

Extra 10, 10 is half of what she ordered so she received an extra 50%

8 0

3 years ago

Read 2 more answers

Let f(x) = x2 – 4, x < 0. What is f-1?

Galina-37 [17]

Answer:

-3

Step-by-step explanation:

f(x) = x2 – 4

replace x with -1

f(-1) = (-1)^2 – 4

= -3

5 0

2 years ago

If the vertex of a parabola is (-4, 6) and another point on the curve is (-3, 14), what is the coefficient of the squared expres

Luda [366]

$\bf \qquad \textit{parabola vertex form}\\\\\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array}\qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex\ (-4,6)\qquad 
\begin{cases}
h=-4\\
k=6
\end{cases}\implies y=a(x-(-4))^2+6
\\\\\\
y=a(x+4)^2+6
\\\\\\
\textit{we also know that }
\begin{cases}
x=-3\\
y=14
\end{cases}\implies 14=a(-3+4)^2+6$

solve for "a"

8 0

3 years ago

A 210-N mass is suspended from a horizontal beam by two cables that make angles of 29 degrees and 53 degrees with the beam. Find

natta225 [31]

The tension in the cable is given by the newton's first law will be 163.622 N.

<h3>What is newton's first law?</h3>

The summation of the force is equal to zero.

The formula is given as

ΣF = 0

Where m is the mass of the body and a is the acceleration.

A 210-N mass is suspended from a horizontal beam by two cables that make angles of 29 degrees and 53 degrees with the beam.

Then the tension in the cable will be

Let T be the tension in the cable.

T sin 29° + T sin 53° – 210 = 0

On simplifying, we have

T (sin 29° + sin 53°) = 210

T = 163.622 N

More about the newton's first law link is given below.

brainly.com/question/974124

#SPJ1

6 0

2 years ago