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Montano1993 [528]
3 years ago
10

What number should be added to -20 to get the sum of 36?

Mathematics
2 answers:
DochEvi [55]3 years ago
4 0

36 - (-20) = 56

SO the number that should be added to -20 to get the answer of 36 is 56.

Hope this helps! Mark as Brainliest please! :)))

nadezda [96]3 years ago
4 0
Well, we need to turn -20 into zero to make it easier. -20’s opposite is 20. So, -20+20=0. Now, what do we add to 0 to get 36? 36, right? So, 0+36 is 36. Now add the numbers we previously added. 20+36=56. So, the number that should be add to -20 to get 36 is 56. Hope this helped!
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10 = 3x – 8<br><br> what is this
Margaret [11]

Answer:

<u><em>Answer is below</em></u>

Step-by-step explanation:

<u><em>10=3x-8</em></u>

<u><em>always remember to flip the equation</em></u>

<u><em>3x-8=10</em></u>

<u><em>Add 8 to both sides</em></u>

<u><em>3x-8(+8)=10(+8)</em></u>

<u><em>3x=18</em></u>

<u><em>Divide both sides by 3</em></u>

<u><em>3x/3=18/3</em></u>

<u><em>x=6</em></u>

8 0
3 years ago
Read 2 more answers
Solve for the variable z to 4 = 8/5
Shkiper50 [21]

Answer:

Alright well solve for z by simplifying by both sides of the equation, then isolating the variable

Exact form: z = 2/5

Decimal form: o.4 Hope this helps :)

Step-by-step explanation:


5 0
3 years ago
Mr. Clark traveled 456.4 km in 14 days.
xeze [42]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

<h3><u>Distance travelled each day is</u> : </h3>

  • 32.6 km

<h3><u>Explanation</u> : </h3>

Distance travelled in 14 days is : 456.4 km

And if he travels same Distance each day, so let the Distance travelled on each day be x

According to question ~

\qquad \sf  \dashrightarrow \: 14 \times x = 456.4

\qquad \sf  \dashrightarrow \: x = 456.4 \div 14

\qquad \sf  \dashrightarrow x = \: 32.6  \: \: km

So, he travels 32.6 km per day

5 0
2 years ago
(CO 4) In a sample of 8 high school students, they spent an average of 24.8 hours each week doing sports with a sample standard
AveGali [126]

Answer:  

(22.12, 27.48)

Step-by-step explanation:

Given : Significance level : \alpha: 1-0.95=0.05

Sample size : n= 8 , which is a small sample (n<30), so we use t-test.

Critical values using t-distribution: t_{n-1,\alpha/2}=t_{7,0.025}=2.365

Sample mean : \overline{x}=24.8\text{ hours}

Standard deviation : \sigma=3.2\text{ hours}

The confidence interval for population means is given by :-

\overline{x}\pm t_{n-1,\alpha/2}\dfrac{\sigma}{\sqrt{n}}

i.e. 24.8\pm(2.365)\dfrac{3.2}{\sqrt{8}}

24.8\pm2.67569206001\\\\\approx24.8\pm2.68\\\\=(24.8-2.68, 24.8+2.68)=(22.12, 27.48)

Hence, the 95% confidence interval, assuming the times are normally distributed.=  (22.12, 27.48)

6 0
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Olin [163]

Answer:

The answer is C, LN and NK hoped I helped

6 0
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