Four friends are standing in line to buy tickets. Carlos is not first in line. Paige is ahead of Kate. Lisa is last in line.

1 answer:

4 0

Well Carlos obviously isn't first, and the question states that Lisa is last.
And Paige is in front of Kate, so the line would go:

Paige
Kate
Carlos
Lise

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Help please

tester [92]

Answer:

64y² - 81

Step-by-step explanation:

(8y +9)(8y - 9)

64y² - 72y + 72y - 81

64y² - 81

6 0

3 years ago

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Write using algebra.<br><br> Jimmy ran m miles in t minutes. What was his speed?

Ilya [14]

Speed = m x t. as the equation

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3 years ago

I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu

ra1l [238]

The imaginary unit $i$ belongs to the set of complex numbers, denoted by $\mathbb C$ . These numbers take the form $a+bi$ , where $a,b$ are any real numbers.

The set of real numbers, $\mathbb R$ , is a subset of $\mathbb C$ , where each number in $\mathbb R$ can be obtained by taking $b=0$ and letting $a$ be any real number.

But any number in $\mathbb C$ with non-zero imaginary part is not a real number. This includes $i$ .

"is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because $2=2+0i$ .

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising $i$ to the $i$ -th power. Since $i=e^{i\pi/2}$ , we have