You put a border around the perimeter of this room. How many yards of border did you

Mathematics

1 answer:

Fantom [35]3 years ago

7 0

Yards of the border is 22 yards.

Step-by-step explanation:

Step 1: Find the perimeter of the room to find the yards of border to be used.

⇒ Perimeter = 2(length + breadth) = 2(6 + 5) = 22 yd

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Sebastian writes the recursive formula f(x+1) = 4f(x) to represent a geometric sequence whose second term is 12.

dexar [7]

Hello,

What do you want?

a(2)=4*a(1)==>a(1)=12/4=3
a(0)=3/4

a(n)=3/4 * 4^n (genearl term)

3 0

3 years ago

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-3x^{2}-21x-54 what are the zeros? (Solutions)

Irina-Kira [14]

The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

x^2+7x+18
a=1
b=7
c=18

x= $\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}$
x= $\frac{-7+/- \sqrt{49-72} }{2}$
x= $\frac{-7+/- \sqrt{-23} }{2}$
i=√-1
x= $\frac{-7+/- i\sqrt{23} }{2}$

the zerose would be
x= $\frac{-7+ i\sqrt{23} }{2}$ or $\frac{-7- i\sqrt{23} }{2}$

4 0

3 years ago

In the regular pentagon below, if AP = 4 m and BC = 10 m, find it's area.

12345 [234]

First symmetrically cut the pentagon to get 5 pieces. (So that you will get the idea that this polygon is divided into 5 triangles)

Then find the area of one of the triangles:

Area of Triangle = $\frac{1}{2} bh$

A = $\frac{1}{2}$ × 4 × 10

A = 20 m²

To find the area of the whole pentagon shape:

A = 20 × 5 = 100 m²

Hope it helps!

4 0

2 years ago

What is the solution of -(x + 1) - 5 > 10

Pie

-(x + 1) - 5 > 10
-x - 1 - 5 > 10
- x - 6 > 10
Add 6 to the both sides,
-x - 6 + 6 > 10 + 6
-x > 16
x < -16 [ changed sign 'cause changed -sign ]

In short, Your Answer would be x < -16

Hope this helps!

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r-ruslan [8.4K]

Answer:

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