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Nonamiya [84]
3 years ago
11

A biology class examined some flowers in a local meadow. Out of the 40 flowers they saw, 8 were perennials. What percentage of t

he flowers were perennials?
Write your answer using a percent sign (%).
Mathematics
1 answer:
Sladkaya [172]3 years ago
4 0
So first we want to say, 8 out of the 40 flowers were perennials.

8 out of 40 is 8/40, or simplified down to 1/5.

1/5 in percentage form is 20% because 1 divided by 5 = 20%.
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I need help plz 8th math
Lemur [1.5K]

Answer:

56°

Step-by-step explanation:

hii!

to solve this, we need to know that the angles of a triangle all add up to 180 degrees.

we are going to make an x equation here.

2x+3x+40=180

5x+40=180

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5x=140

/5   /5

x=28

angle a is 2x, so the answer would be 28*2 which is 56°

hope this helped out :)

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The grades on a physics midterm at Covington are roughly symmetric with = 72 and = 2.0. Stephanie scored 74 on the exam. Find th
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Answer:1.00

Step-by-step explanation:

A=74-72/2.0

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Write the equation of a line with slope 3 and passing through the point (1,-1)
pychu [463]

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Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

3 0
3 years ago
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