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2 years ago

Equation for the area of a circle with a diameter of 31.6 cm. Use 3.14 for

Mathematics

2 answers:

goldfiish [28.3K]2 years ago

6 0

Answer:

783.8696

Step-by-step explanation:

The way to find the area of a circle is to find the radius, multiply it by itself, then multiply by pi. The diameter is double the radius so we have to divide the diameter by 2 to find the radius. 31.6/2 is equal to 15.8, and if we plug it into our formula, we can find that the area is 15.8 * 15.8 * pi, and since we use 3.14 for pi, the area is 15.8 * 15.8 * 3.14. We can use a calculator for this part and find that the area of this circle is 783.8696.

tester [92]2 years ago

6 0

Area of a circle is PI x r^2

You are given the diameter, the radius is half the diameter:

Area - PI x 1/2(diameter)^2

Area = 3.14 x 1/2(31.6)^2

Area = 3.14 x 15.8^2

Area = 3.14 x 249.64

Area = 783.8696 sq. cm. ( Round answer as needed)

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Find the pressure exerted by a force of 240 N on an area of 30 cm2. Find the answer in SI unit

NeTakaya

Answer:

Pressure is 80,000 pascals.

Step-by-step explanation:

Area:

$= { \bf{ 30 \times {10}^{ - 4} \: {m}^{2} }}$

Pressure:

${ \bf{pressure = \frac{force}{area} }} \\ \\ { \tt{ = \frac{240}{30 \times {10}^{ - 4} } }} \\ = { \tt{80000 \: pascals}}$

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2 years ago

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melisa1 [442]

Answer:

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2 years ago

Find the surface area of this cube. Be sure to include the correct unit in your answer

alexandr1967 [171]

Answer:

384 inches squared

Step-by-step explanation:

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4 0

2 years ago

A man hits a baseball when it is 4 ft above the ground with an initial velocity of 120 ft/sec. The ball leaves the bat at a 30 d

Sauron [17]

et us assume that the origin is the floor right below the 30 ft. fence

To work this one out, we'll start with acceleration and integrate our way up to position.

At the time that the player hits the ball, the only force in action is gravity where: a = g (vector)
ax = 0
ay = -g (let's assume that g = 32.8 ft/s^2. If you use a different value for gravity, change the numbers.

To get the velocity of the ball, we integrate the acceleration
vx = v0x = v0cos30 = 103.92
vy = -gt + v0y = -32.8t + v0sin40 = -32.8t + 60

To get the positioning, we integrate the speed.
x = v0cos30t + x0 = 103.92t - 350
y = 1/2*(-32.8)t² + v0sin30t + y0 = -16.4t² + 60t + 4

If the ball clears the fence, it means x = 0, y > 30

x = 0 -> 103.92 t - 350 = 0 -> t = 3.36 seconds

for t = 3.36s,
y = -16.4(3.36)^2 + 60*(3.36) + 4
= 20.45 ft

which is less than 30ft, so it means that the ball will NOT clear the fence.

Just for fun, let's check what the speed should have been :)

x = v0cos30t + x0 = v0cos30t - 350
y = 1/2*(-32.8)t² + v0sin30t + y0 = -16.4t² + v0sin30t + 4

x = 0 -> v0t = 350/cos30
y = 30 ->
-16.4t^2 + v0t(sin30) + 4 = 30
-16.4t^2 + 350sin30/cos30 = 26
t^2 = (26 - 350tan30)/-16.4
t = 3.2s

v0t = 350/cos30 -> v0 = 350/tcos30 = 123.34 ft/s

So he needed to hit the ball at at least 123.34 ft/s to clear the fence.

You're welcome, Thanks please :)

6 0

2 years ago

Write an equation of the line satisfying the given conditions. Through (2, -5), parallel to 5x 6y + 7

mojhsa [17]

We have to determine the equation of the line passing through the point (2,-5) and parallel to the line $5x = 6y+7$