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siniylev [52]
3 years ago
6

The mean of the data set is 40 and one standard deviation is 5. About what percent of the numbers fall between 35 and 50?

Mathematics
1 answer:
Nataly [62]3 years ago
8 0

Answer:

The correct option is D. 81.8%

Step-by-step explanation:

Mean of the data set is given to be 40

⇒ μ = 40

Standard deviation of the data set is given to be 5

⇒ σ = 5

Now we are supposed to find out what percent of the numbers fall between 35 and 50

\implies z =\frac{x-\mu}{\sigma}

Now for P(35 < x < 50) :

Substitute x = 35 ⇒ z = -1

Substitute x = 50 ⇒ z = 2

So, P(-1 < z < 2) = P(z < 2) - P(z < -1)

⇒ P(-1 < z < 2) = 0.9772 - 0.1587

⇒ P(-1 < z < 2) = 0.8185

⇒ P(-1 < z < 2) = 81.8%

Therefore, 81.8% percent of the numbers fall between 35 and 50

Hence, The correct option is D. 81.8%

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2 years ago
What is -7/ 12 plus 7/10 in simplest form
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So, your final answer is 7/60

Hope this helps!
6 0
3 years ago
Read 2 more answers
Hi!
solniwko [45]

Answer:

y = 1x - 4

Step-by-step explanation:

You have to solve for the x intercept on the equation

2x-5y=8\\2x-5(0)=8\\2x=8\\x=4\\(4,0)

That is the x intercept for that equation.

Then solve for the y intercept on the equation

4x-3y=12\\4(0)-3y=12\\-3y=12\\y=-4\\(0,-4)

That is the x intercept for that equation.

Use that to find slope for point slope form

\frac{y_{2}-y_{1}}{x_{2}-_{1}} \\\\\frac{-4-0}{0-4} \\\\\frac{-4}{-4} \\\\1

1 is the slope

and slope makes B the y intercept so the equation is

y = 1x - 4

8 0
3 years ago
Length of a rectangle is four times its width. If the perimeter is 100 m, what is the area in square cm?
melisa1 [442]

Set the width to be x. Thus, the length is 4x.

The perimeter is 2(x+4x)=100, so x=10.

Plugging in x=10, you get that 4x=40.

So, the area of the rectangle is 400 m^2.

Because there are 100 centimeters in a meter and you are asking for area, you must multiply by 100^2 to get 4000000 cm^2.


6 0
3 years ago
What is the solution to the equation -4 (2x + 3) = 2x + 6 - (8x + 2)
jeka94

Answer:

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Step-by-step explanation:

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