<span>Multiply one of the equations so that both equations share a common complementary coefficient.
In order to solve using the elimination method, you need to have a matching coefficient that will cancel out a variable when you add the equations together. For the 2 equations given, you have a huge number of choices. I'll just mention a few of them.
You can multiply the 1st equation by -2/5 to allow cancelling the a term.
You can multiply the 1st equation by 5/3 to allow cancelling the b term.
You can multiply the 2nd equation by -2.5 to allow cancelling the a term.
You can multiply the 2nd equation by 3/5 to allow cancelling the b term.
You can even multiply both equations.
For instance, multiply the 1st equation by 5 and the second by 3. And in fact, let's do that.
5a + 3b = –9
2a – 5b = –16
5*(5a + 3b = -9) = 25a + 15b = -45
3*(2a - 5b = -16) = 6a - 15b = -48
Then add the equations
25a + 15b = -45
6a - 15b = -48
=
31a = -93
a = -3
And then plug in the discovered value of a into one of the original equations and solve for b.</span>
Answer:
Step-by-step explanequation of line passing through (x₁,y₁):-
y-y₁=m(x-x₁)
The equation of line which passes through (4,3) and slope is 5/4
y-3=5/4(x-4)
4y-12=5x-20
5x-4y-8=0ation:
7x+2=23
Move 2 to the other side
7x=23-2
7x=21
To isolate the x divide both sides by 7
x=3
To check plug the value of x back in
7(3)+2=23
21+2=23
23=23
Answer:
<ONP and <MNP
Step-by-step explanation:
Answer:
x = 8
Step-by-step explanation:
Since the triangle is right use Pythagoras' identity to solve for x
The square on the hypotenuse is equal to the sum of the squares on the other two sides, thus
x² + 6² = 10²
x² + 36 = 100 ( subtract 36 from both sides )
x² = 64 ( take the square root of both sides )
x = 
= 8
