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Lelu [443]
3 years ago
11

An AP news service story, printed in the Gainesville Sun on May 20, 1979, states the following with regard to debris from Skylab

striking someone on the ground: "The odds are 1 in 150 that a piece of Skylab will hit someone. But 4 billion people ... live in the zone in which pieces could fall. So any one person’s chances of being struck are one in 150 times 4 billion—or one in 600 billion." Do you see any inaccuracies in this reasoning?
Mathematics
1 answer:
blondinia [14]3 years ago
5 0

Answer:

  • The odds are one in approximately 27 million.
  • Not one in 600 billion

Step-by-step explanation:

From the news story, we are told that:

The odds are 1 in 150 that a piece of Skylab will hit someone.

However, 4 billion people live in the zone in which pieces could fall.

Therefore, any one person’s chances of being struck are:

=\dfrac{1}{150} \times 4$ billion\\=\dfrac{1}{37.5}$ billion\\\\=26,666,667 million

Therefore, the odds are one in approximately 27 million.

The inaccuracy presented in this reasoning was that the odds are one in 600 billion.

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The width of a rectangle is the length minus 2 units. The area of the rectangle is 48 units. What is the width, in units, of the
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Step-by-step explanation:

Remember the formula for the area of a rectangle: A = lw

What we know:

A=48

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Substitute A for 48 and w for l-2 into the equation

A = lw

48 = l(l-2)   Use the distributive property. Multiply over the brackets.

48 = l² - 2l

Rearrange the equation to standard form (0 = ax² + bx + c) to use quadratic formula.

0 = l² - 2l - 48

a = 1 ; b = -2 ; c = -48   State the variables for the quadratic formula

Substitute a, b and c to find the length:

l = \frac{-b± \sqrt{b^{2}-4ac} }{2a}

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l = \frac{2± \sqrt{4-(-192)} }{2}

l = \frac{2± \sqrt{196} }{2}

l = \frac{2± 14 }{2}  

Split the equation at the ± for adding and subtracting. Then decide which answer is correct, or if both of them are possible answers.

l = \frac{2- 14 }{2}

l = \frac{-12 }{2}

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Use the formula for the area of a rectangle

Substitute the length and area, then isolate "w" for the width

A = lw

48 = (8)w

48/8 = w

w = 6

Therefore the length of the rectangle is 6 units.

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4 years ago
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