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3 years ago

name the lengths of the sides of three rectangles with perimeters of 14 units. use only whole numbers.

Mathematics

1 answer:

Lady bird [3.3K]3 years ago

3 0

rectangle 1: 6 units by 1 unit

rectangle 2: 5 units by 2 units

rectangle 3: 4 units by 3 units

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Divide these numbers in the given ratios:

Digiron [165]

Dont know but mabye someone who is not 8 will know

4 0

3 years ago

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Simplify the expression. 64 7/12<br> 16<br> 8 √2<br> 4√2<br> 32

mezya [45]

Answer:

$8\sqrt2$

Second option is correct.

Step-by-step explanation:

We have been given the expression $(64)^{\frac{7}{12}}$

We can write the term 64 as $64=2^6$

Thus, we have

$(2^6)^{\frac{7}{12}}$

Now, use the exponent law $(x^m)^n=x^{mn}$

$(2)^{6\cdot\frac{7}{12}}$

On simplifying, we get

$(2)^{\frac{7}{2}}$

This expression can be further simplified as

$\sqrt{2^7}\\\\=\sqrt{2^6\cdot2}\\\\=2^3\sqrt{2}\\\\=8\sqrt2$

Second option is correct.

8 0

3 years ago

3t + 8 (2t - 6) = 2 + 14t

xz_007 [3.2K]

Answer: t=10

Step-by-step explanation:

FOIL 8(2t-6)= 16t-48

Combine like terms 3t+16t-48=2+14t becomes 19t-48=2+14t

Put all t's on same side 19t-14t=2+48

5t=50 Divide by 5 on each side to have t by self

8 0

3 years ago

Find the slope of the line shown on the graph to the right.

Nostrana [21]

Answer:

slope=5/6

Step-by-step explanation:

m=y2-y1/x2-x1

3-(-2)=5

2-(-4)=6

5/6

hope this helps :3

if it did pls mark brainliest

6 0

3 years ago

Read 2 more answers

Which equation represents a line that passes through (4,1/3) and has a slope of 3/4?

velikii [3]

We can use the point-slope equation:
$y = mx + b$
m, the slope, is 3/4:
$y = \frac{3}{4} x + b$
To find b, we plug in the point (4,1/3):
$( \frac{1}{3} ) = \frac{3}{4} (4) + b \\ \frac{1}{3} = 3 + b \\ \frac{1}{3} = \frac{9}{3} + b$
$- \frac{8}{3} = b$

Therefore, the point-slope equation is
$y = \frac{3}{4} x - \frac{8}{3}$

Now we have to see which answer matches.

$y - \frac{3}{4} = \frac{1}{3} (x - 4) \\ y - \frac{3}{4} = \frac{1}{3} x - \frac{4}{3} \\ y - \frac{9}{12} = \frac{1}{3} x - \frac{16}{12}$
$y = \frac{1}{3} x - \frac{7}{12}$
Since this is not the same, we try the next one.

$y - \frac{1}{3} = \frac{3}{4} (x - 4) \\ y - \frac{1}{3} = \frac{3}{4} x - 3 \\ y - \frac{1}{3} = \frac{3}{4} x - \frac{9}{3}$
$y = \frac{3}{4} x - \frac{8}{3}$

This is the same, so this is the answer. We should still double-check the other answers.

$y - \frac{1}{3} = 4(x - \frac{3}{4} ) \\ y - \frac{1}{3} = 4x - 3 \\ y - \frac{1}{3} = 4x - \frac{9}{3}$
$y = 4x - \frac{8}{3}$
This one is not equivalent.

$y - 4 = \frac{3}{4} (x - \frac{1}{3} ) \\ y - 4 = \frac{3}{4} x - \frac{1}{4} \\ y - \frac{16}{4} = \frac{3}{4} x - \frac{1}{4}$
$y = \frac{3}{4} x + \frac{15}{4}$
This one also does not work.

The answer is the second one:
$y - \frac{1}{3} = \frac{3}{4} (x - 4)$

3 0

3 years ago

Read 2 more answers