Answer:
Step-by-step explanation:
C=0.14×7,200=1008
Nadia made a total of $1008 last week in commission sales
b). To express the total amount she made in 2011, we derive the formula below;
Total amount (2011)=Average weekly commission× number of weeks in 2011
where;
Average weekly commission=$1008
number of weeks in 2011=52
replacing;
Total amount (2011)=(1008×52)=52,416
The total amount Nadia in commission in 2011=$52,416
The value of x is ![5\sqrt[3]{25}](https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7B25%7D)
.
Solution:
Given expression is ![-7=8-3 \sqrt[5]{x^{3}}](https://tex.z-dn.net/?f=-7%3D8-3%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D)
.
Switch both sides.
![8-3 \sqrt[5]{x^{3}}=-7](https://tex.z-dn.net/?f=8-3%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%3D-7)
Subtract 8 from both side of the equation.
![8-3 \sqrt[5]{x^{3}}-8=-7-8](https://tex.z-dn.net/?f=8-3%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D-8%3D-7-8)
![-3 \sqrt[5]{x^{3}}=-15](https://tex.z-dn.net/?f=-3%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%3D-15)
Divide by –3 on both side of the equation.
![$\frac{-3 \sqrt[5]{x^{3}}}{-3} =\frac{-15}{-3}](https://tex.z-dn.net/?f=%24%5Cfrac%7B-3%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%7D%7B-3%7D%20%3D%5Cfrac%7B-15%7D%7B-3%7D)
![\sqrt[5]{x^{3}}=-5](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%3D-5)
To cancel the cube root, raise the power 5 on both sides.
![(\sqrt[5]{x^{3}})^5=(-5)^5](https://tex.z-dn.net/?f=%28%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%29%5E5%3D%28-5%29%5E5)
To find the value of x, take square root on both sides.
![\sqrt[3]{x^3}=\sqrt[3]{25}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%3D%5Csqrt%5B3%5D%7B25%7D)
![x=5\sqrt[3]{25}](https://tex.z-dn.net/?f=x%3D5%5Csqrt%5B3%5D%7B25%7D)
Hence the value of x is .
Answer:
56x+21
Step-by-step explanation:
7times 8x is 56x
7 times 3 is 21
add them together and you get 56x+21
Answer:
The value of x is 16
Step-by-step explanation:
In the right triangle of the length of the hypotenuse c and the lengths of two legs a and b
- a² + b² = c² ⇒ Pythagoras Theorem
In the given figure
∵ The right triangle has two legs of lengths 8√2, 8√2
∴ a = 8√2 and b = 8√2
∵ It has a hypotenuse of length x
∴ c = x
→ Substitute them in the rule above
∵ (8√2)² + (8√2)² = x²
∵ (8√2)² = (8)²(√2)² = (64)(2) = 128
∴ 128 + 128 = x²
∴ 256 = x²
→ Take a square root for both sides
∵ √256 = √(x)²
→ The root will cancel power 2 of x
∴ 16 = x
∴ The value of x is 16
