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Liono4ka [1.6K]
3 years ago
14

Find the lesser of two consecutive integers with a sum greater than 15

Mathematics
1 answer:
sweet [91]3 years ago
6 0

Let n and n+1 be two consecutive integers. Their sum is n+n+1=2n+1.

Then if a sum is greater than 15, then

2n+1>15,

2n>15-1,

2n>14,

n>7.

The smallest n, such that n>7 is n=8, then n+1=9.

Answer: 8, 9.

You might be interested in
8x^3+4x^2–2x+6<br> —————————-<br> 4x^2
miv72 [106K]

Answer:

2( 4x^3 + 2x^2 - x + 3/4x^2)

Step-by-step explanation:

Factor 2 out of the equation

8 0
3 years ago
Read 2 more answers
19 is 10% of what number
hram777 [196]
19=10%X. 19/.10=190. X=190 :)
7 0
4 years ago
Read 2 more answers
2/3 of the product of 3/8 and 16
kakasveta [241]
Hi there!

To solve this problem, we should first find the product of 3/8 and 16 and multiply the solution by 2/3.

Let's find the product first.

3/8 × 16 = 48/8

Simplify.

48/8 = 48 ÷ 8 = 6

Now, we find 2/3 of 6.

6 ÷ 3 × 2 = 2 × 2 = 4

So, your answer is 4.

Hope this helps!
7 0
3 years ago
How do I find X for 3x-7=5x-13?
Westkost [7]
3x - 7 = 5x - 13
-3x        -3x

5x - 3x = 2x

-7 = 2x - 13
+7         +7

-13+7 = -6

2x = -6
2x/2 = -6/2
x = -3

Answer: x = -3
6 0
3 years ago
Pls help solve this problem
eduard

Answer:

  166 mm²

Step-by-step explanation:

The area is given by ...

  A = (1/2)Pa . . . . . where P is the perimeter and "a" is the apothem

One side of a 6-sided figure is shown as 8 mm, so the perimeter is ...

  P = 6·(8 mm) = 48 mm

Filling in the apothem value, we have ...

  A = (1/2)(48 mm)(4√3 mm) = 96√3 mm² ≈ 166 mm²

The area of the hexagon is about 166 mm².

4 0
3 years ago
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