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3 years ago

Anyone know how to solve this??

Mathematics

1 answer:

Tom [10]3 years ago

7 0

$Given : \frac{(x^\frac{2}{5})^9\;.\;(x^\frac{-4}{15})}{x^\frac{1}{3}}$

$\implies {(x^\frac{18}{5})\;.\; (x^\frac{-4}{15})}\;.\;(x^\frac{-1}{3})$

$\implies x^(^\frac{18}{5} ^-^\frac{4}{15}^-^\frac{1}{3}^)$

$\implies x^(^(^\frac{54 - 4}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{50}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{10}{3}^)^-^\frac{1}{3}^) = x^(^\frac{9}{3}^) = x^3$

$\implies x^k = x^3$

$\implies k = 3$

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You Just received a 6 percent raise in allowance or an increase of 312.00 per year how much per year were you earning before the

Alona [7]

before the raise you were earning 100% of "x", we also know that 6% of "x" is 312, since that is what you've got in the raise, therefore

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2 years ago

The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 91 inches, and a standard d

Vesna [10]

The sample std. dev. will be (14 inches) / sqrt(49), or (14 inches) / 7, or 2 inches.

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93.8 inches - 91.0 inches 2.8 inches
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2 inches 2 inches

Now find the area under the standard normal curve to the left of z = +1.4.

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4 0

3 years ago

Find the measure of each angle.

Galina-37 [17]

Given:

Given that the isosceles trapezoid JKLM.

The measure of ∠K is 118°

We need to determine the measure of each angle.

Measure of ∠L:

By the property of isosceles trapezoid, we have;

$\angle K+\angle L=180^{\circ}$

$118^{\circ}+\angle L=180^{\circ}$

$\angle L=62^{\circ}$

Thus, the measure of ∠L is 62°

Measure of ∠M:

By the property of isosceles trapezoid, we have;

$\angle L \cong \angle M$

Substituting the value, we get;

$62^{\circ}=\angle M$

Thus, the measure of ∠M is 62°

Measure of ∠J:

By the property of isosceles trapezoid, we have;

$\angle J \cong \angle K$

Substituting the value, we get;

$\angle J =118^{\circ}$

Thus, the measure of ∠J is 118°

Hence, the measures of each angles of the isosceles trapezoid are ∠K = 118°, ∠L = 62°, ∠M = 62° and ∠J = 118°

4 0

3 years ago

Describe how the product of 0.4 × 2 would look on a ten-square grid. The product would have _____ squares shaded out of 10.

krek1111 [17]

0.8 squares shaded out of 10

You just do 4x2 which is 8

Then add the 0. In front of 8

Easy as that

8 0

3 years ago

Please help with my math

shusha [124]

Answer:

Step-by-step explanation:

These triangles are similar triangles, so there is a number that you can multiply the sides of TUV to find the side lengths of QRS. looking at the triangle, the similar sides are RS being similar to UV and RQ being similar to UT.

If RS~UV, then there is a ratio between them. 54/36=1.5. The ratio is 1.5.

RQ~UT, and by a factor of 1.5, so divide RQ by the scale factor. 24/1.5=16. UT=16=x+5.

x+5=16, subtract 5 from both sides.

x=11

5 0

3 years ago