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Mkey [24]
3 years ago
8

Anyone know how to solve this??

Mathematics
1 answer:
Tom [10]3 years ago
7 0

Given : \frac{(x^\frac{2}{5})^9\;.\;(x^\frac{-4}{15})}{x^\frac{1}{3}}

\implies {(x^\frac{18}{5})\;.\; (x^\frac{-4}{15})}\;.\;(x^\frac{-1}{3})

\implies x^(^\frac{18}{5} ^-^\frac{4}{15}^-^\frac{1}{3}^)

\implies x^(^(^\frac{54 - 4}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{50}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{10}{3}^)^-^\frac{1}{3}^) = x^(^\frac{9}{3}^) = x^3

\implies x^k = x^3

\implies k = 3

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