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3 years ago

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Mathematics

2 answers:

AleksAgata [21]3 years ago

7 0

The answer is C it is 37%

mrs_skeptik [129]3 years ago

3 0

The Answer is <em>C </em>

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Cell phone users can obtain a clear signal when they are within a 42−mile radius of cell tower A. The radius that cell tower B c

Basile [38]

Answer:

It will have 16 times more coverage than cell tower A.

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3 years ago

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Use the equation A = bh to calculate the height of a parallelogram with an area of 36 square inches and a base of 9 inches

hichkok12 [17]

Answer:

4 inches

Step-by-step explanation:

A = b x h

A = 36

b = 9

36 = 9 x h

4 = h

height = 4 inches

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2 years ago

Find the value of x and the measure of each labeled angle. (8x - 20ºX (5x + 37)

11111nata11111 [884]

According to above figure, the angles (8x - 20)° and (5x + 37)° are pairs of vertical opposite angles, so

8x - 20 = 5x + 37

8x - 5x = 37 + 20

3x = 57

x = 57 ÷ 3

x = 19

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3 years ago

Evaluate 2 ∙ (8 + 4) using the steps of order of operations.

Natalka [10]

Step-by-step explanation:

Follow PEMDAS

$2 ∙ (8 + 4)$

P: Parentheses

E : Exponents

M: Multiplication

D: Division

A: Addition

S: Subtraction

$2 \cdot \: (12) \\ = 2 \times 12 \\ 24$

Question 2

$15 + 6 \times 3 \\ 15 + (6 \times 3) \\ 15 + 18 \\ = 33$

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3 years ago

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) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

8 0

3 years ago