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3 years ago

7

HELP ME PLSSSSSS!!!!!!!!!!!!!!!

1 answer:

xxMikexx [17]3 years ago

6 0

Answer:

<em>No.</em>

Step-by-step explanation:

<em>5c-6=4-3c</em>

<em>5c-6+6=4-3c+6 Add six to both sides</em>

<em>5c=-3c+10 Simplify</em>

<em>5c+3c=-3c+10+3c Add 3c to both sides</em>

<em>8c=10 Simplify</em>

<em>8c/8=10/8 Divide both sides by 8</em>

<em>c=5/4 <<< Simplify and you get that</em>

<em>So they (Student A) are/is not correct.</em>

Hope this helps, have a good day. c;

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olga2289 [7]

A^3
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3 years ago

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seropon [69]

Answer:

counfsed so can u write it in english ?

Step-by-step explanation:

4 0

3 years ago

If you get a sneak peak at the salary list of your job and realize you are in the lowest bracket, which is the lowest 1%, what i

hoa [83]

Answer:

$z=-2.33$

And if we solve for a we got

$a=48000 -2.33*5500=35185$

And for this case the answer would be 35185 the lowest 1% for the salary

Step-by-step explanation:

Let X the random variable that represent the salary, and for this case we can assume that the distribution for X is given by:

$X \sim N(48000,5500)$

Where $\mu=48000$ and $\sigma=5500$

And we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.99$ (a)

$P(X$ (b)

We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.01 of the area on the left and 0.99 of the area on the right it's z=-2.33. On this case P(Z<-2.33)=0.01 and P(z>-2.33)=0.99

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=-2.33$

And if we solve for a we got

$a=48000 -2.33*5500=35185$

And for this case the answer would be 35185 the lowest 1% for the salary

7 0

3 years ago

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

<u>Find the area of the triangle</u>

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

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3 years ago

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Solve each system of equations; nonlinear algebra 2<br><br> x2 + x + y - 26 = 0<br> x + y = 1

BigorU [14]

Answer:

(5,-4) and (-5,6)

Step-by-step explanation:

Given:

$\left\{\begin{array}{l}x^2+x+y-26=0\\ \\x+y=1\end{array}\right.$

Solve it. First, express y in terms of x from the second equation:

$y=1-x$

Substitute it into the first equation:

$x^2+x+1-x-26=0\\ \\x^2-25=0\\ \\(x-5)(x+5)=0$

Apply zero product property:

$x-5=0\ \text{or}\ x+5=0$

So,

$x=5\ \text{or}\ x=-5$

When $x=5,$ then $y=1-5=-4$

When $x=-5,$ then $y=1-(-5)=6$

We get two solutions: (5,-4) and (-5,6)

8 0

3 years ago