Answer:
Step-by-step explanation:
The coefficients of the quadratic x^2 + 7x + 3 are a = 1, b = 7 and c = 3.
The discriminant is b^2 - 4ac, or 49 - 4(1)(3), or 49-12, or 37.
Because the discriminant is positive, we know that this quadratic equation has two real, different solutions.
-7 ± √37
x = --------------- => x = (-7 + √37)/2 and x = (-7 - √37)/2
2
In words: This quadratic equation has two real, unequal solutions involving the radicand 37.
Answer:
see explanation
Step-by-step explanation:
For the triangles to be congruent.
The hypotenuse and a leg of the triangle on the left and the hypotenuse and a leg of the triangle on the right must be congruent, thus
4y = x + 4 → (1)
x = y + 8 → (2)
Substitute x = y + 8 into (1)
4y = y + 8 + 4 = y + 12 ( subtract y from both sides )
3y = 12 ( divide both sides by 3 ) )
y = 4
Substitute y = 4 into (2)
x = 4 + 8 = 12
Thus
x = 12 and y = 4
7/8=x/8
if x/y=z/y where y=y, then x=z
we have
7/8=x/8
8=8
therefor 7=x
the missing value=7
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