Use the graph below to find f(1)

Can someone heelp me with this i just dont understand it

poizon [28]

Answer:

I CAN!

Step-by-step explanation:

First, where does the line start?

y=1

It looks like it goes up, and then right each one unit. No?

So that would be

Y=1+1

Warning! DO NOT say y=2. That is no good. You probably want to simplify it, but dont. Okay?

Happy to help

ОωО

6 0

2 years ago

Find a polynomial function of degree 3 with 2, i, -i as zeros.

sergiy2304 [10]

Answer:

$p(x)= x^3-2x^2+x-2$

Step-by-step explanation:

Here we are given that a polynomial has zeros as 2 , i and -i . We need to find out the cubic polynomial . In general we know that if $\alpha , \ \beta \ \& \ \gamma$ are the zeros of the cubic polynomial , then ,

$\sf \longrightarrow p(x)= (x -\alpha )(x-\beta)(x-\gamma)$

Here in place of the Greek letters , substitute 2,i and -i , we get ,

$\sf\longrightarrow p(x)= (x -2 )(x-i)(x+i)$

Now multiply (x-i) and (x+i ) using the identity (a+b)(a-b)=a² - b² , we have ,

$\sf \longrightarrow p(x)= (x-2)\{ x^2 - (i)^2\}$

Simplify using i = √-1 ,

$\sf \longrightarrow p(x)= (x-2)( x^2 + 1 )$

Multiply by distribution ,

$\sf \longrightarrow p(x)= x(x^2+1) -2(x^2+1)$

Simplify by opening the brackets ,

$\sf\longrightarrow p(x)= x^3+x-2x^2-2$

Rearrange ,

$\sf\longrightarrow \underline{\boxed{\blue{\sf p(x)= x^3-2x^2+x-2}}}$

4 0

2 years ago

What are the missing statement and reason in step 2 of the proof? Statement: ∠ABC ≅ ∠BCD, ∠BAD ≅ ∠ADC Reason: For parallel lines

ICE Princess25 [194]

Answer:

Statement: AB=CD, BC=AD

Reason: By definition of parallelogram .

Statement: AC=AC

Reason: Reflexive property of equality.

Step-by-step explanation:

1.Statement: $\angle ABC\cong \angle BCD,\angle BAD\cong \angle ADC$ .

Reason: For parallel lines cut by a transversal , corresponding angles are congruent.

2.Statement:AB=CD,BC=AD

Reason: By definition of parallelogram.

3.Statement: AC=AC

Reason: Reflexive property of equality.

4.Statement: $\triangle ABC\cong \triangle CDA$ .

Reason: SSS criterion for congruence.

5.Statement: $AB\cong CD, BC\cong AD$ .

Reason: Given .

6.Statement: $AB\parallel CD, BC\parallel AD$ .

Reason: By definition of parallelogram.

7.Statement: $\angle BAC\cong \angle ACD$ .

Reason: Alternate Interior Angles Theorem.

7 0

2 years ago

Carlita secret recipe for turkey surprise (Original)

Liula [17]

Answer:

I don't get what you are trying to ask?

6 0

3 years ago

2. The acute angle below has a degree measurement that is one fifth of the degree measure of the obtuse

Ksenya-84 [330]

Answer:

Acute angle = 30°

Obtuse angle = 150°

Step-by-step explanation:

Method 1:

Let x represent the measurement of the obtuse angle

Obtuse angle = x

Acute angle = ⅕ of x = x/5

Thus:

x + x/5 = 180° (angels on a straight line)

Solve for x

(5x + x)/5 = 180

Multiply both sides by 5

5x + x = 180 × 5

6x = 900

x = 900/6

x = 150

Obtuse angle = 150°

Acute angle = x/5 = 150/5 = 30°

Method 2:

Since acute angle = ⅕ of the obtuse angle, therefore,

Obtuse angle = 5*acute angle

Let acute angle = x

Obtuse angle = 5x

Equation:

5x + x = 180° (angles on a straight line)

Solve for x

6x = 180

x = 180/6

x = 30

Acute angle = x = 30°

Obtuse angle = 5x = 5*30 = 150°

8 0

2 years ago