In kite ABCD, AB = BC and CD = DA. AB = (3x + 4), BC = x + 8, CD = y + 7, and DA = 2y + 5, find the perimeter of the kite
1 answer:
3x + 4 = x+ 8 > 3x - x = 2x > 2x + 4 = 8 > 8 - 4 = 4 > 2x / 2 crosses out > 4 / 2 = 2 > x=2
2y + 5 = y + 7 > 2y - y = y > y+ 5 = 7 > 7-5= 2 > y=2
the perimeter of the kite is 4
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