The two linear equations in two variable is:
12 x + 3 y = 40
7 x - 4 y = 38
(a) For a system of equations in two Variable
a x + by = c
p x + q y = r
It will have unique solution , when

As, you can see that in the two equation Provided above

So, we can say the system of equation given here has unique solution.
(b). If point (2.5, -3.4) satisfies both the equations, then it will be solution of the system of equation, otherwise not.
1. 12 x+3 y=40
2. 7 x-4 y=38
Substituting , x= 2.5 , and y= -3.4 in equation (1) and (2),
L.H.S of Equation (1)= 1 2 × 2.5 + 3 × (-3.4)
= 30 -10.20
= 19.80≠ R.H.S that is 40.
Similarly, L H S of equation (2)= 7 × (2.5) - 4 × (-3.4)
= 17.5 +13.6
= 31.1≠R HS that is 38
So, you can Write with 100 % confidence that point (2.5, -3.4) is not a solution of this system of the equation.
Answer:
8 kittens
Step-by-step explanation:
so is 17 kittens are napping do that minus 9 you can use tally marks if u like
Answer:
PEMDAS
Step-by-step explanation:
First you do the numbers in the parentheses and the exponents
Then you do any multiplication or division in the problem.
Finally, you do any addition or subtraction in the problem.
*All of this should be done from left to right
5a+2a(5−b)
Distribute:
=5a+(2a)(5)+(2a)(−b)
=5a+10a+−2ab
Combine Like Terms:
=5a+10a+−2ab
=(−2ab)+(5a+10a)
=−2ab+15a
Answer:
AH = 
Step-by-step explanation:
The opposite sides of a rectangle are congruent , so
GH = RA = 7
Using Pythagoras' identity in right Δ GHA
AH² + GH² = GA²
AH² + 7² = 10²
AH² + 49 = 100 ( subtract 49 from both sides )
AH² = 51 ( take the square root of both sides )
AH =
≈ 7.14 ( to 2 dec. places )