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4 years ago

What is the solution to the system of equations? Use any method.

Mathematics

1 answer:

vichka [17]4 years ago

3 0

Answer:

x=3 and y=-1

Step-by-step explanation:

2x-3y=9

3x+5y=4

Change equations in order to make a variable cancel out. In this case, multiply the top by -3 and the bottom by 2

-6x+9y=-27

6x+10y=8

Add the equations

19y=-19

y=-1

Plug in y=-1 into any equation

2x-3(-1)=9

2x+3=9

2x=6

x=3

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American Airlines charges $270 for a flight to Denver and $50 for each piece of luggage. Delta Airlines charges $330 for a fligh

amm1812

Answer:

J; 250 + 50x > 330 + 30x

Step-by-step explanation:

Since we don't have to worry about formatting the numbers to slope-intercept form, we can start the process of elimination.

First, we can disregard G and H because both have the x in the wrong place:

—> F 270 + 50x ≥ 330 + 30x

—> G 270x + 50 > 330x + 30

—> H 270x + 50 < 330x +30

—> J 270 + 50x > 330 + 30x

We're looking for <em>270 + 50x > 330 + 30x</em>.

Next, we determine which symbols are correct. Since the question is only asking for when American Airlines would be more expensive, not when it would be just as much or more, we can get rid of F.

—> F 270 + 50x ≥ 330 + 30x

—> J 270 +50x > 330 + 30x

We finally have our answer, J.

5 0

3 years ago

From the top of a tree a bird looks down on a field mouse at an angle of depression of 50°. If the field mouse is 40 meters from

solong [7]

Answer:

The vertical distance from the ground to the bird's eyes is 47.67 m

Step-by-step explanation:

* Lets explain the situation of the problem

- There is a bird on the top of a tree

- The bird looks down on a field mouse at an angle of depression of 50°

- The field mouse is 40 meters from the base of the tree

* Consider that the vertical distance from the ground to the bird's eyes,

the distance from the field mouse to the base of the tree distance

from the bird eyes to the field mouse formed a right triangle

- The hypotenuse is the distance from the bird eyes to the field mouse

- The horizontal side is the distance from the field mouse to the base

of the tree

- The angle between the hypotenuse and the horizontal side is the

angle of depression which = 50°

- The opposite side to the angle of measure 50° is the vertical distance

from the ground to the bird's eyes

* Lets use trigonometry functions to find the vertical distance

∵ The length of the adjacent side to the angle of measure 50° is 40 m

∵ The length of the opposite side to the angle of measure 50° is h m

∵ tan Ф = opposite side to Ф ÷ adjacent side to Ф

∵ Ф = 50°

∴ tan 50° = h/40 ⇒ by using cross multiplication

∴ 40 tan 50° = h

∴ h = 47.67 m

* The vertical distance from the ground to the bird's eyes is 47.67 m

3 0

3 years ago

The weight distribution of parcels sent in a certain manner is normal with mean value 15 lb and standard deviation 3.3 lb. The p

disa [49]

Answer: 23.7 lb

Step-by-step explanation:

Mean m = 15 lb

Standard deviation d = 3.3 lb

To determine the surcharge weight, we need to know the highest weight of 99% of the parcels.

P(z<x) = 0.99 = ¢(Z)

Z = 2.33

Since Z = (x - m)/d

x = dZ + m

x = 3.3*2.33 + 15

x = 22.689 lb approximately

x = 22.7 lb

Therefore, the highest weight for 99% if the parcels is 22.7 lb.

That is, the surcharge weight = 22.7 + 1 = 23.7 lb

3 0

3 years ago

Answer this question correctly and i'll give u brainliest pls

rusak2 [61]

Answer:

Corresponding angles

Step-by-step explanation:

They have the same relative position to the parallel lines (in blue)

6 0

3 years ago

Read 2 more answers

What are the zeros of the quadratic function f(x) = 2x2 + 8x – 3?

crimeas [40]

Answer:

$\large\boxed{x=-2-\sqrt{\dfrac{11}{2}}\ \text{and}\ x=-2+\sqrt{\dfrac{11}{2}}}$

Step-by-step explanation:

$f(x)=2x^2+8x-3\\\\\text{You can use the quadratic formula:}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\text{We have}\ a=2,\ b=8,\ c=-3\\\\\text{Substitute:}\\\\b^2-4ac=8^2-4(2)(-3)=64+24=88\\\\\sqrt{b^2-4ac}=\sqrt{88}=\sqrt{4\cdot22}=\sqrt4\cdot\sqrt{22}=2\sqrt{22}\\\\x=\dfrac{-8\pm2\sqrt{22}}{2(2)}=\dfrac{-8}{4}\pm\dfrac{2\sqrt{22}}{4}=-2\pm\dfrac{\sqrt{22}}{2}=-2\pm\dfrac{\sqrt{22}}{\sqrt4}\\\\x=-2\pm\sqrt{\dfrac{22}{4}}=-2\pm\sqrt{\dfrac{11}{2}}$

5 0

3 years ago

Read 2 more answers