Answer:
4x-y+1=0
Step-by-step explanation:
here,given equation of a line id
4x-y-2=0.. eqn(i)
equation of any line parallel to line (i) is
4x-y+k=0...eqn(ii)
since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]
4*1-5+k=0
or, 4-5+k=0
or,-1+k=0
•°•k=1
substituting the value of k=1 in eqn(ii),
4x-y+1=0 is the required equation of the line.
Answer:
12
Step-by-step explanation:
The answer is 145 divided by tan 65 degrees.
Since the equation for tangent is opposite/adjacent, you can just plug the numbers in.
tan(65)=145/x (x being the height that you are trying to find)
tan(65) * x = 145
Then divide tan(65) to isolate the x and you get:
145/tan(65)
Hope this helps!
The solid line indicates that the line itself is included in the solutions. That the shaded area is to the left, or under, the line means that y≤the line.
To find the equation of the line you first find the slope or m using any two points.
m=(y2-y1)/(x2-x1) in this case you are given (2,-5) and (-2, 3) so
m=(3--5)/(-2-2)
m=8/-4
m=-2
So far for y≤mx+b we have:
y=-2x+b using either point we can solve for b, I'll use (2,-5)
-5=-2(2)+b
-5=-4+b
-1=b
So the line is:
y=-2x-1 and since y≤ the line:
y≤-2x-1
