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postnew [5]
3 years ago
13

Sam has read 3/6 of his assessments Judy has read 4/8 of her assessments their assessments where the same size which is true

Mathematics
1 answer:
Shtirlitz [24]3 years ago
7 0
Sam and Judy read the same amount of their assessments.
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The average local cell phone call length was reported to be 2.27 minutes. A random sample of 20 phone calls showed an average of
Afina-wow [57]

Answer:

Yes, at α = 0.05 it can be concluded that the average differs from the population average.

Step-by-step explanation:

We are given that the average local cell phone call length was reported to be 2.27 minutes. A random sample of 20 phone calls showed an average of 2.98 minutes in length with a standard deviation of 0.98 minutes.

<em>Let </em>\mu<em> = population average local cell phone call length</em>

SO, Null Hypothesis, H_0 : \mu = 2.27 minutes  {means that the average is same as that of population average}

Alternate Hypothesis, H_a : \mu \neq 2.27 minutes  {means that the average differs from the population average}

The test statistics that will be used here is <u>One-sample t test statistics </u>because we don't know about population standard deviation;

                T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average call length = 2.98 minutes

            s = sample standard deviation = 0.98 minutes

            n = sample of phone calls = 20

So, <em><u>test statistics</u></em>  =  \frac{2.98-2.27}{\frac{0.98}{\sqrt{20} } }  ~ t_1_9

                               =  <u>3.24</u>

Now, at 0.05 level of significance the t table gives critical values between -2.093 and 2.093 at 19 degree of freedom for two-tailed test. Since our test statistics does not lie within these range of critical values so we have sufficient evidence to reject our null hypothesis as test statistics will fall in the rejection region.

Therefore, we conclude that the average differs from the population average.

6 0
3 years ago
34=2m-8. Solve the equation
N76 [4]
The equation will be m=21
7 0
3 years ago
Read 2 more answers
Can you solve them with points to plot thank you
BigorU [14]

I have solved the first one. Hope this helps

8 0
3 years ago
Help me pleasee (10 points)
Montano1993 [528]

Answer:

B

Step-by-step explanation:

Givens

a^2 + b^2 = c^2

a = 4x

b = x + 2

c = 3x + 4

Solution

(4x)^2 + (x + 2)^2 = (3x + 4)^3                  Remove all the brackets.

16x^2 + x^2 + 4x + 4 = 9x^2 + 24x + 16  Collect like terms on the left

17x^2 + 4x + 4 = 9x^2 + 24x + 16            Subtract the terms on the right

8x^2 - 20x - 12 = 0

This factors into

(4x - 12)(2x + 1)

There are 2 answers

4x - 12 = 0

4x = 12

x = 12/4

x = 3

or

2x + 1 = 0

2x = - 1

x = - 1/2

You have to look at x = -1/2 carefully. The problem is that 4x = 4*(-1/2) = - 2 which is not possible in Euclidean Geometry.

So the only answer is x = 3

4 0
2 years ago
Please help me!!! what is the average of 24, 38, and 19?
faust18 [17]
You have to add up all the numbers then divide by the amount of numbers there are
24+38+19=81
81/3=27
The average is 27
6 0
3 years ago
Read 2 more answers
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