Try to understand this. Hope this help. Answer for 2 only.
The first term of the arithmetic progression exists at 10 and the common difference is 2.
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How to estimate the common difference of an arithmetic progression?</h3>
let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.
We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula
The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.
9th term = 50
a + 8d = 50 ...............(1)
12th term = 65
a + 11d = 65 ...............(2)
subtract them, (2) - (1), we get
3d = 15
d = 5
If a + 8d = 50 then substitute the value of d = 5, we get
a + 8
5 = 50
a + 40 = 50
a = 50 - 40
a = 10.
Therefore, the first term is 10 and the common difference is 2.
To learn more about common differences refer to:
brainly.com/question/1486233
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Answer:
13 is Prime
Step-by-step explanation:
Answer:
cosM ≈ 0.3048
Step-by-step explanation:
remember SOH CAH TOA = sine: opposite/hypotenuse; cosine: adjacent/hypotenuse; tangent: opposite/adjacent
cos = CAH
cosM= a / c
cosM = 4.0 / 13.1244
cosM = 0.30477
cosM ≈ 0.3048
Refer to the figure shown below.
The coordinates of point m are (2,5).
Let (x,y) = the coordinates of pont n.
Because mn = 4, use the Pythagorean theorem to obtain
(x - 2)² + (y - 5)² = 4²
This represents a circle with center at (2,5) and radus = 4.
Answer:
Possible coordinates for n lie on the circle (x-2)² + (y-5)² = 16.