Option C:
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Solution:
Area of the square paper = 
sq. cm
Area of the square corner removed = 16 sq. cm
Let us find the area of the remaining paper.
Area of the remaining paper = Area of the square paper – Area of the corner
Area of the remaining = 
= 
Using algebraic formula: 
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Hence (3x – 4)(3x + 4) represents area of the remaining paper in square centimeters.
Answer:
3/14
Step-by-step explanation:
6/7 ÷ 4
Copy dot flip
6/7 * 1/4
Rewriting
6/4 * 1/7
Divide the top and the bottom of the first fraction by 2
3/2 * 1/7
3/14
The ratio of red to green is 5:6 which means that for every 5 red cars, there are 6 green cars
The ratio of green to blue is 3:10 telling us that for every 3 green cars, there are 10 blue cars.
The ratio 3:10 is equivalent to 6:20 after we multiply both parts by 2. This now says that for every 6 green cars, there are 20 blue cars.
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Let's say we had 5 red cars, 6 green cars and 20 blue cars
Based on that info, we know that the ratio of red to green is 5:6
And the ratio of green to blue is 6:20 which reduces to 3:10
We don't reduce 6:20 to 3:10 however, since that would change the green count from 6 to 3. We want to keep the green count at 6.
So because there are 5 red cars, 6 green cars, and 20 blue cars in this example, and this example points to the proper ratios mentioned earlier, this means that the final answer is 5:6:20. This ratio cannot be reduced or simplified as there are no common factors (other than 1) for 5, 6, and 20.
Answer:
its B
Step-by-step explanation:
Answer:
The endpoints of the midsegment for △DEF that is parallel to DE, are (-1,3.5) and (-1,2).
Step-by-step explanation:
If a line connecting the midpoint of two sides and parallel to the third side of the triangle, then it is called a midsegment.
From the given figure it is noticed that the vertices of the triangle are D(1,4), E(1,1) and F(-3,3).
If the midsegment is parallel to DE, then the end points of the midsegment are mid point of DF and EF.
Midpoint formula.
Midpoint of DF,
Midpoint of EF,
Therefore the endpoints of the midsegment for △DEF that is parallel to DE, are (-1,3.5) and (-1,2).
