All categories

3 years ago

Write 6/7 as a decimal rounded to the nearest hundredth

Mathematics

1 answer:

Travka [436]3 years ago

5 0

Answer:

0.01

Step-by-step explanation:

6/7% = 6÷7÷100 = 0.0085714286 round to the nearest hundredth = 0.01

You might be interested in

Eric goes to the grocery store to buy apples so that he can bake an apple pie He can buy 2 apples for $150 or 6 apples

PIT_PIT [208]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Any answers help please! show your work

DiKsa [7]

1. -√8, -2.1, 3/2, 12/6, 4

sorry man I'm tired but here's ya first set of answers

4 0

3 years ago

PLEASE HELP 25 POINTS!!

iris [78.8K]

Answer:

m= masters degree salary and b=bachelors degree salary.

m = 2b - 45000

m + b = 112000

Substitute to get

2b - 45000 + b = 112000

3b = 156000

b = 52000

So m = 59000

Check to see if these numbers work

59000 = 2*52000 - 45000 true

59000 + 52000 = 112000 true

Step-by-step explanation:

7 0

3 years ago

Solve the quadratic equation x2=25/36.<br><br><br>What are the solutions of the equation x2=25/36?

Alinara [238K]

Answer:

x is equal to positive 5/6 and negative 5/6

Step-by-step explanation:

To solve this, you simply need to take the square root of both sides:

$x^2 = \frac{25}{36}\\\sqrt{x^2} = \sqrt{\frac{25}{36}}\\x = \pm \frac{5}{6}$

7 0

3 years ago

A study conducted at a certain high school shows that 72% of its graduates enroll at a college. Find the probability that among

mixas84 [53]

Answer:

$P(X \geq 1) =1-P(X$

And we can use the probability mass function and we got:

$P(X=0)=(4C0)(0.72)^0 (1-0.72)^{4-0}=0.00615$

And replacing we got:

$P(X \geq 1) = 1-0.00615 = 0.99385$

Step-by-step explanation:

Let X the random variable of interest "number of graduates who enroll in college", on this case we now that:

$X \sim Binom(n=4, p=0.72)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We want to find the following probability:

$P(X \geq 1)$

And we can use the complement rule and we got:

$P(X \geq 1) =1-P(X$

And we can use the probability mass function and we got:

$P(X=0)=(4C0)(0.72)^0 (1-0.72)^{4-0}=0.00615$

And replacing we got:

$P(X \geq 1) = 1-0.00615 = 0.99385$

5 0

3 years ago