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Dima020 [189]
3 years ago
11

Stella wants to buy colored pencils that cost $3.50. She has 1 dollar, 5 quarters, 4 dimes, and 7 pennies. Does she have enough

money to buy the colored pencils?
Mathematics
1 answer:
Andrews [41]3 years ago
6 0

Answer:

no

Step-by-step explanation:

Lets she how much money she has

1.00   dollars

5 * .25 = 1.25 quarters

4 * .10 = .40 dimes

7 * .01 = .07 pennies

Add it all together

1 + 1.25+ .40 +.07 =2.72

3.50 - 2.72 =.78

She is 78 cents short

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What is the graph of y=-(x-2)^3-5
natulia [17]
When x=0,
y=-(0-2)^3-5
y=3

When y=0,
(x-2)^3=5
x-2= +/- 5^1/3
x= +/- 5^1/3 +2
x= 3.70997 or x=0.29002

To find the turning point at y, substitute the information that you have found above.

y=-(3.70997-2)^3-5
y=-9.99994

Find the mid-point next as mid-point is also the turning point.

(3.70997+0.29002)÷2=1.999995

Hence, Turning point is (1.999995, 9.99994)

Plot a graph using turning point, y value and the 2-x values.
6 0
4 years ago
Which expressions are equivalent to 7b(3+c)
steposvetlana [31]
The answers are expressions:
(7b*3)+(7b*c)
21b+7bc
I hope I helped!
8 0
3 years ago
What is the answer to this problem
Umnica [9.8K]

Answer:

42

Step-by-step explanation:

ABC + CBD = ABD

3x+33 + 5x+13 = 70

Combine like terms

8x +46 = 70

Subtract 46 from each side

8x+46-46 = 70-46

8x = 24

Divide each side by 8

8x/8 = 24/8

x=3

We want to find ABC

ABC = 3x+33 = 3*3 +33 = 9+33 = 42

4 0
3 years ago
Read 2 more answers
How can I do 30-4 as a mixed number
sertanlavr [38]
30 over 4 = 15·2 over 2·2 = 15 over 2 = 1 + 7·2 over 2 = 7 1 over 2
Whole number =7
Fraction = 1 over 2

Hope this helps
6 0
3 years ago
The sum of the first 10 terms of an arithmetic sequence is 235 and the
Degger [83]

Answer:

             \bold{a_1 = -42.65}\\\\\bold{d=14.7}

Step-by-step explanation:

The sum of the first 10 terms of an arithmetic sequence is:

S_{10}=a_1+a_2+...+a_{10}=\dfrac{a_1+a_{10}}{2}\cdot10=\dfrac{2a_1+(10-1)d}{2}\cdot10

\dfrac{2a_1+(10-1)d}{2}\cdot10=235\\\\(2a_1+9d)\cdot5=235\\\\2a_2+9d=47

the  sum of the second 10 terms is:  a₁₁ + a₁₂+...+ a₂₀

And the sum of the first 20 terms of an arithmetic sequence is:

S_{20}=a_1+a_2+...+a_{10}+a_{11}+...+a_{20}=\dfrac{2a_1+(20-1)d}{2}\cdot10

so the  sum of the second 10 terms is:

a_{11}+a_{12}+...+a_{20}=S_{20}-S_{10}

Therefore we have:

\dfrac{2a_1+(20-1)d}{2}\cdot10-\dfrac{2a_1+(10-1)d}{2}\cdot10=735\\\\(2a_1+19d)\cdot5-(2a_1+9d)\cdot5=735\\\\2a_1+19d-(2a_1+9d)=147\\\\10d=147\\\\d=14.7

and:  

2a_1+9\cdot14.7=47\\\\2a_1+132.3=47\\\\2a_1=-85.3\\\\a_1=-42,65

3 0
3 years ago
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