Answer:
x = 6, y = -6
Step-by-step explanation:
solve for x and y
x + 3y = -12
y + 3 = -x + 3
add
(x + 3y) + -x + 3 = -12 + y + 3
3y + 3 = y - 9
2y + 3 = -9
2y = -12
y = - 6
x + 3(-6) = -12
x - 18 = -12
x = 6
Equivalent expressions are expressions of equal values
The equivalent expressions are 4x+ (y - 8y) + (2z-5z) +6 and 6x-3x-6x + (2y - 10y) + (4 - 8) + (z - 88z)
<h3>How to determine the equivalent expressions</h3>
The first expression has been solved.
So, we have the following expressions
4x−7y−5z+6 and -3x−8y−4−87z
<u>4x−7y−5z+6</u>
We have:
4x-7y-5z+6
Rewrite as:
4x+ (y - 8y) + (2z-5z) +6
<u>-3x−8y−4−87z</u>
We have:
-3x−8y−4−87z
Rewrite as:
3x-6x + (2y - 10y) + (4 - 8) + (z - 88z)
Hence, the equivalent expressions are 4x+ (y - 8y) + (2z-5z) +6 and 6x-3x-6x + (2y - 10y) + (4 - 8) + (z - 88z)
Read more about equivalent expressions at:
brainly.com/question/2972832
I'm guessing on the make up of the matrices.
First off let's look at [C][F].
[C]=
[F]=
[C][F]=
where each element of [C][F] comes from multiplying a row of [C] with a column of [F].
Example: First element is product of first row and first column.
.
.
.
Now that we have [C][F], we can subtract it from [B], element by element,
[B]-[C][F]=
[B]-[C][F]=
.
.
.
If this is not how the matrices look,please re-state the problem and be more specific about the make up of the matrices (rows x columns).
Here's an example.
[A] is a 2x2 matrix. A=[1,2,3,4].
The assumption is that [A] looks like this,
[A]=
[B] is a 3x2 matrix. B=[5,6,7,8,9,10]
[B]=
we have
Find the roots
Equate the function to zero
Group terms that contain the same variable, and move the constant to the opposite side of the equation
Complete the square. Remember to balance the equation by adding the same constants to each side.
Rewrite as perfect squares
Square root both sides
therefore
<u>the answer is</u>
Answer:
{2, 4}.
Step-by-step explanation:
A = {1, 2, 3, 4, 5} and B = {2, 4}.
A ∩ B?
This means intersection or what is in common
A ∩ B = {2, 4}.
