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777dan777 [17]
4 years ago
7

How do I do the work

Mathematics
1 answer:
IgorC [24]4 years ago
8 0
16+5 [61-(5.6)]
16+5 (61-30)
16+5*31
16+155
171
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Renata and david want to cover the walls in one room of their house with wall paper.
valkas [14]
For this case we have the following variables:
 P = area covered by a roll of wallpaper
 w = the total area of the walls
 n = number of rolls to buy
 We write the equation for n.
 You must take into account that you can determine this amount by dividing the total area between the area covered by each roll of paper.
 We have then:
 n = w / P
 
 Answer:
 
a formula that will help them determine how much wall paper they'll need to purchase is:
 n = w / P
3 0
4 years ago
Help me! Im having trouble if you can please answer and give an explanation! The best one will get brainlist!
jasenka [17]
For the second work sheet:
5 2/8 - 4 1/4= 1 so NO
8 3/4 - 7 1/2= 1 1/4 so YES
2 1/8 - 1 7/8= 1/4 so NO
9 5/12 - 8 1/6= 1 1/4 so YES
Sorry if its not enough explanation, hope it helps!
8 0
3 years ago
In angle ABC, what is the measure of angle B?<br> 46°<br> 48<br> 70°<br> 92
fiasKO [112]
The answer is 46. All equal to 46%
4 0
4 years ago
The two lines y= 6x+15 and y= mx+4 intersect at x= -2. What is the y-coordinate of their intersection point
taurus [48]

Answer:

The y-coordinate of their intersection point is 3

That is y=3

Step-by-step explanation:

Given two lines are y=6x+15 and y=mx+4

Given that the two lines intersect at x=-2

To find the y coordinate of their intersection point :

Equating the two lines

6x+15=mx+4

6x+15-mx-4=0

6x-mx+11=0

(6-m)x+11=0

At x=-2  (6-m)x+11=0

(6-m)(-2)+11=0

(6-m)(-2)=-11

6-m=\frac{11}{2}

-m=\frac{11}{2}-6

-m=\frac{11-12}{2}

-m=\frac{-1}{2}

m=\frac{1}{2}

Substitute the value m=\frac{1}{2} in y=mx+4 we get

y=\frac{1}{2}x+4

At x=-2 y=\frac{1}{2}(-2)+4

=-1+4

=3

Therefore y=3

Therefore the y-coordinate of their intersection point is 3

7 0
3 years ago
A Simple random sample of 100 8th graders at a large suburban middle school indicated that 84% of them are involved with some ty
Setler [38]

Answer: a) (0.755, 0.925)

Step-by-step explanation:

Let p be the population proportion of 8th graders are involved with some type of after school activity.

As per given , we have

n= 100

sample proportion: \hat{p}=0.84

Significance level : \alpha= 1-0.98=0.02

Critical z-value : z_{\alpha/2}=2.33  (using z-value table)

Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

i.e. 0.84\pm (2.33)\sqrt{\dfrac{0.84(1-0.84)}{100}}

i.e. \approx0.84\pm 0.085

i.e. (0.84- 0.085,\ 0.84+ 0.085)=(0.755,\ 0.925)

Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)

3 0
4 years ago
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