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3 years ago

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Last question please help

1 answer:

Grace [21]3 years ago

4 0

Juan won and has a score of 8.5, the difference between there score is 3.5.

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Three different rectangles have an area of 20. What are the possible whole-number dimensions of the rectangles?

Firlakuza [10]

L = 20 W = 1
L = 10 W = 2
L = 5 W = 4

Study this carefully. It's a good problem to know how to do. The ancients solved problems by using this method. They started with biggest number they could on the left and multiply each number on the right as they went down (in this case by 2).

4 0

4 years ago

Which expression is equivalent to 128x^5y^6 \ 2x^7y^5 ? Assume x > 0 and y > 0.

N76 [4]

Answer: Last option.

Step-by-step explanation:

Given the expression:

$\sqrt{\frac{128x^5y^6}{2x^7y^5}$

The Quotient of powers property states that:

$\frac{a^m}{a^n}=a^{(m-n)}$

And the Power of a powet property states that:

$(a^m)^n=a^{mn}$

Then, applying these properties, you get:

$=\sqrt{\frac{(2^3)^26y}{x^2}$

Now you must remember that:

$\sqrt[a]{a^n}=a$

Therefore, simpliying the expression, you get:

$=\frac{2^3\sqrt{y}}{x}=\frac{8\sqrt{y}}{x}$

7 0

3 years ago

Read 2 more answers

Can someone help me please it’s urgent

laila [671]

Answer:

use the x and y method and try to apply it with the 3 given expressions

7 0

3 years ago

PLEASE HELP!!! Write the equation of a line that goes through the point (6, 3) and is perpendicular to the line y = 4x + 1.

Tpy6a [65]

For this case we have that by definition, the equation of a line in the point-slope form is given by:

$y-y_ {0} = m (x-x_ {0})$

Where:

m: It is the slope of the line and $(x_ {0}, y_ {0})$ is a point through which the line passes.

We have the following equation of the slope-intersection form:

$y = 4x + 1$

Where the slope is $m = 4$

By definition, if two lines are perpendicular then the product of their slopes is -1.

Thus, a perpendicular line will have a slope:

$m_ {2} = \frac {-1} {m_ {1}}\\m_ {2} = \frac {-1} {4}\\m_ {2} = - \frac {1} {4}$

Thus, the equation will be of the form:

$y-y_ {0} = - \frac {1} {4} (x-x_ {0})$

Finally we substitute the given point and we have:

$y-3 = - \frac {1} {4} (x-6)$

Answer:

Option B

8 0

3 years ago

The table shows a proportional relationship. Select the missing y-value.

Alenkinab [10]

Answer:

A 24

Step-by-step explanation:

8 0

3 years ago