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jonny [76]
3 years ago
6

Last question please help

Mathematics
1 answer:
Grace [21]3 years ago
4 0
Juan won and has a score of 8.5, the difference between there score is 3.5.
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At a real estate​ agency, an agent sold a house for ​$323,000. The commission rate is 6.5​% for the real estate agency and the c
Lady_Fox [76]

Answer:

20,0995 or 80,750

hope this helps sorry if im wrong

Step-by-step explanation:

4 0
3 years ago
Solve the proportion<br>16/6 = 3s/9
iris [78.8K]

Answer:

8

Step-by-step explanation:

So you can start by simplifying each fraction:

16/6 divide by 2/2 = 8/3

3s/9 divided by 3/3 = s/3

Then, since 8/3 = s/3 you just have s = 8.

4 0
3 years ago
To solve for y in the equation 2y + y = 5, what first step would need to be taken? Subtract 2 from each side. Add 2y and y. Subt
cricket20 [7]

Answer:

Add 2y and y.

Step-by-step explanation:

you have to combine what is common

plz give brainliest

4 0
3 years ago
PLEASE HELP ILL GIVE BRAINLIEST
dusya [7]

1)

(-2+\sqrt{-5})^2\implies (-2+\sqrt{-1\cdot 5})^2\implies (-2+\sqrt{-1}\sqrt{5})^2\implies (-2+i\sqrt{5})^2 \\\\\\ (-2+i\sqrt{5})(-2+i\sqrt{5})\implies +4-2i\sqrt{5}-2i\sqrt{5}+(i\sqrt{5})^2 \\\\\\ 4-4i\sqrt{5}+[i^2(\sqrt{5})^2]\implies 4-4i\sqrt{5}+[-1\cdot 5] \\\\\\ 4-4i\sqrt{5}-5\implies -1-4i\sqrt{5}

3)

let's recall that the conjugate of any pair a + b is simply the same pair with a different sign, namely a - b and the reverse is also true, let's also recall that i² = -1.

\cfrac{6-7i}{1-2i}\implies \stackrel{\textit{multiplying both sides by the denominator's conjugate}}{\cfrac{6-7i}{1-2i}\cdot \cfrac{1+2i}{1+2i}\implies \cfrac{(6-7i)(1+2i)}{\underset{\textit{difference of squares}}{(1-2i)(1+2i)}}} \\\\\\ \cfrac{(6-7i)(1+2i)}{1^2-(2i)^2}\implies \cfrac{6-12i-7i-14i^2}{1-(2^2i^2)}\implies \cfrac{6-19i-14(-1)}{1-[4(-1)]} \\\\\\ \cfrac{6-19i+14}{1-(-4)}\implies \cfrac{20-19i}{1+4}\implies \cfrac{20-19i}{5}\implies \cfrac{20}{5}-\cfrac{19i}{5}\implies 4-\cfrac{19i}{5}

7 0
2 years ago
Read 2 more answers
A sum of scalar multiples of two vectors (such as au + bv, where a and b are scalars) is called a linear conbination of the vect
belka [17]

Answer:

  -4u -5v

Step-by-step explanation:

Let the sum be ...

  <3, -27> = a<3, 3> +b<-3, 3>

This resolves to two equations

  3 = 3a -3b

  -27 = 3a +3b

Adding these together, we get

  -24 = 6a

  a = -4

Substituting into the second equation gives ...

  -27 = 3(-4) +3b

  -15 = 3b

  -5 = b

The desired linear combination is ...

  <3, -27> = -4<3, 3> -5<-3, 3> = -4u -5v

6 0
3 years ago
Read 2 more answers
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