Answer:
x = ± 1 , x = ± 
Step-by-step explanation:
Let u = x² , then
- 3x² + 2 = 0 , can be expressed as
u² - 3u + 2 = 0 ← in standard form
(u - 1)(u - 2) = 0 ← in factored form
Equate each factor to zero and solve for u
u - 1 = 0 ⇒ u = 1
u - 2 = 0 ⇒ u = 2
Change the variable u back to x
x² = 1 ( take square root of both sides )
x = ± 1
or
x² = 2 ( take square root of both sides )
x = ±
Answer:
232 in squared
Step-by-step explanation:
Find the area of one face and multiply it by 2
7 x 4 x 2=56
4 x 8 x 2=64
7 x 8 x 2=112
Add and you get 232
Hello from MrBillDoesMath!
Answer:
x = 2 and 10
Discussion:
Approach 1:
20 = (-10)*(-2) and (-10) + (-2) = -12 the coefficients of the polynomial. Hence
x^2 -12x + 20 = ( x- 2) * ( x-10)
Approach 2:
From the quadratic formula ( a = 1, b = -12, c = 20)
x = ( -(-12) +\- sqrt( ((-12)^2 - 4*1*20) ) / (2 * 1)
= ( 12 +\- sqrt( 144-80) ) /2
= (12 +\- sqrt(64) ) /2
= (12 +\- 8 ) /2
x = ( 12 + 8) /2 = 20/2 = 10
or
x = ( 12 - 8)/ 2 = 4/2 = 2
Thank you,
MrB
The radical equation is
.
i) We first isolate the square root, adding 5 to both sides of the equation:
ii) Here let's substitute x+6 with t. Doing so we have:
Squaring both sides, we get:
iii) Collecting the variables on the same side, and factorizing t we have:
, which yields
t=0 or t=1.
Now we solve for x in x+6=t:
x+6=0 ⇒x=-6 and x+6=1⇒x=-5.
iv) Now we check these values in the original equation
:
a)
⇒ 0=0 ; Correct.
b)
⇒ 1=1 ; Correct.
Answer: <span>x = −6 and x = −5 </span>
