Answer:
The answer is D
Step-by-step explanation:
Answer:

Step-by-step explanation:
Consider irght triangle PRS. By the Pythagorean theorem,

Thus,

Consider isosceles triangle MSC. In this triangle

The area of this triangle is

Consider right triangle PTS. The area of this triangle is

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

I would graph the points and find the equation
Answer: 6.
Step-by-step explanation:
4^2 = 16
10 − 16 + 6 * 2
6 * 2 = 12
10 − 16 + 12
10 - 16 = -6
-6 + 12 = 6
Answer:
a) x1 = 6 and x2 = -2
b) -2
Step-by-step explanation:
a)
To find the roots of the quadratic equation, we can use the Bhaskara's formula:
Delta = b^2 - 4ac
Delta = (-4)^2 - 4*1*(-12) = 64
sqrt(Delta) = 8
x1 = (-b + sqrt(Delta)) / 2a
x1 = (4 + 8) / 2
x1 = 6
x2 = (-b - sqrt(Delta)) / 2a
x2 = (4 - 8) / 2
x2 = -2
b)
The roots are 6 and -2, so the smaller root is -2