Siny/2.7=sin63/2.8
siny=2.7sin63/2.8
y=arcsin((2.7sin63)/2.8)
y≈59.23° (to nearest one-hundredth of a degree)
8(1-8p) + 8p
8 - 64p + 8p
8 - 56p
8 = 56p
1/7 = p
Answer:
Step-by-step explanation:
Correct option is
D
[1,(1+π)
2
]
f(x)=(1+sec
−1
(x))(1+cos
−1
(x))
Here the limiting component is cos
−1
(x), since the domain of cos
−1
(x) is [−1,1].
Therefore,
f(1)=(1+0)(1+0)
=1
f(−1)=(1+π)(1+π)
=(1+π)
2
Hence range of f(x)=[1,(1+π)
2
]
Answer:
C. The situation represents a geometric sequence because the successive y-values have a common ratio of 1.05.
Step-by-step explanation:
The initial number of accidents = 5200 = Po
It increases 5% every year.
So r = 5% = 0.05
y = Po(1 + r)^x
y = 5200(1 + 0.05)^x
y = 5200(1.05)^x
This sequence is an exponential. Which is a geometric sequence.
Answer: C. The situation represents a geometric sequence because the successive y-values have a common ratio of 1.05.
Thank you.
