Find the difference between the actual and the estimated values of 55 - 21
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Answer:
Assuming the area is made up of a square and a semicircle.
<u>Perimeter</u>
The side length of the square = 18 ft
We can see 3 full side lengths plus one side length from which we need to subtract 12 ft (see attached diagram).
⇒ perimeter of the square = (3 x 18) + (18 - 12)
= 54 + 6
= 60 ft
Circumference of a circle = d (where d is the diameter)
⇒ arc length of the semicircle = 1/2 circumference
= 1/2 · · 12
= 6 ft
Total perimeter = 60 + 6 = 78.8 ft (nearest tenth)
<u>Area</u>
Area of a square = s² (where s is the side length)
⇒ area of square = 18²
= 324 ft²
Diameter = 2r ⇒ r = 1/2 diameter
Area of a circle = r² (where r is the radius)
⇒ area of the semicircle = 1/2 · · 6²
= 18 ft²
Total area = 324 + 18 = 380.5 ft² (nearest tenth)
