Answer:
Step-by-step explanation:
16.25pi
You can get this by first solving for volume of a cylender formula for the 1.5 radius of the outer shell. Then solve for a 1 radius of the inner empty portion. Then subtract the second from the first.
Plug the points into the distance formula.
d= (sqrt) (x2-x1)^2+(y2-y1)^2
Plug the first set of points in. (-2,1) (6,1)
d= (sqrt) (6-(-2))^2+(1-1)^2
d= (sqrt) (6+2)^2+(0)^2
d= (sqrt) 8^2+0
d= (sqrt) 64
d= 8
Now, find the distance for the other two points. (6,1) (6,-3)
Q to R.
d= (sqrt) (x2-x1)^2+(y2-y1)^2
d= (sqrt) (6-6)^2 +(-3-1)^2
d= (sqrt) 0^2+-4^2
d= (sqrt) 16
d= 4
Now, finally, find the distance between R and S. (6,-3) and (9,-3)
d= (sqrt) (x2-x1)^2 + (y2-y1)^2
d= (sqrt) (9-6)^2+ (-3-(-3)^2
d= (sqrt) 3^2+ 0^2
d= (sqrt) 9
d= 3
Now, add all those distances together.
8+4+3= 15
"B" is the correct answer. 15 units.
I hope this helps!
~kaikers
