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fomenos
3 years ago
15

The length of a rectangle is 5 in more than double the width

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
3 0

Answer:

length of a rectangle is 5 more than twice the length. I believe

you mean the length of a rectangle is 5 more than twice the

width.

From the information given we can make two equations,

thus forming a system to solve. We know the perimeter

of a rectangle is 2(length + width) and area = length*width.

length of a rectangle is 5 more then twice the width:

L = 2w + 5

The perimeter is 130:

2(L+w) = 130

L+w = 65

Since we know L=2w+5 we can substitute that into 2nd equation

to solve for w

2w + 5 + w = 65

3w = 60

w = 20

L = 2w+5 = 45

The area is length*width = 20(45) = 900 square units

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<h3>First three round</h3>

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14 + 1 = 15

15 + 1 = 16

The above values follow a number series such that we have;

<h3>Fourteenth three rounds</h3>

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3 + 1 = 4

4 - 3 = 1

2 + 1 = 3

1 + 1 = 2

<h3>Fifteenth three rounds</h3>

3 - 3 = 0

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2 + 1 = 3

3 - 3 = 0

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3 - 3 = 0

0 + 1 = 1

1 + 1 = 2

Therefore, after the fifteenth three rounds, which is 15 × 3 = <u>45 rounds</u> Ava runs out of token, ending the game.

Learn more about number series here:

brainly.com/question/4163549

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3 years ago
How does the method for solving equations with fractional or decimal coefficients and constants compare with the method for solv
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Answer:

Step-by-step explanation:

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6 0
3 years ago
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5 0
3 years ago
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How to solve -2(v-2)=-3-2v i need it step by step
Goryan [66]

Answer:O0

Step-by-step explanation:

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STEP

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3 years ago
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Answer:

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Step-by-step explanation:

Given data

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Let us find the amount of the tax and the tip

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Hence the total amount paid is

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=$50

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3 years ago
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