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3 years ago

Simplify for a = 3, b= -4 and c=-1. 16a - 3c + 5b =

Mathematics

1 answer:

-Dominant- [34]3 years ago

5 0

Answer:

Step-by-step explanation:

16(3)-3(-1)+5(-4)

48+3-20

51-21

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bixtya [17]

It would be 56 seconds until both flicker at the same time

have a happy day :)

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3 years ago

Read 2 more answers

HELP ME PLEASE URGENT BRAINLY + 5 STAR

notsponge [240]

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3 years ago

If you know that the exact volume of a cylinder is 500 π cm3, how can you find the approximate volume, without knowing the heigh

grandymaker [24]

Answer:

The approximate volume is $1,570\ cm^{3}$

Step-by-step explanation:

we know that

The exact volume of the cylinder is

$V=500\pi \ cm^{3}$

To find the approximate volume of the cylinder, substitute the term $\pi$ by the approximate value of $3.14$ and then multiply

$V=500(3.14)=1,570\ cm^{3}$

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3 years ago

An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th

butalik [34]

Answer:

a) A sample size of 5615 is needed.

b) 0.012

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

99.5% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.9975$ , so $Z = 2.81$ .

(a) Past studies suggest that this proportion will be about 0.2. Find the sample size needed if the margin of the error of the confidence interval is to be about 0.015.

This is n for which M = 0.015.

We have that $\pi = 0.2$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.015 = 2.81\sqrt{\frac{0.2*0.8}{n}}$

$0.015\sqrt{n} = 2.81\sqrt{0.2*0.8}$

$\sqrt{n} = \frac{2.81\sqrt{0.2*0.8}}{0.015}$

$(\sqrt{n})^{2} = (\frac{2.81\sqrt{0.2*0.8}}{0.015})^{2}$

$n = 5615$

A sample size of 5615 is needed.

(b) Using the sample size above, when the sample is actually contacted, 12% of the sample say they are not satisfied. What is the margin of the error of the confidence interval?

Now $\pi = 0.12, n = 5615$ .