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3 years ago

9

If f(x) = x - 5 then match each of the following.

1 answer:

iogann1982 [59]3 years ago

4 0

1. e 2. b 3. d 4. a 5. c 6. c

please vote my answer brainliest. thanks!

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Write the given logarithmic equation in exponential form.<br><br> In 4x = 9.6

KengaRu [80]

90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love you

7 0

3 years ago

Select all the values that cannot be probabilities a. 3/5b. 1c. -0.45d. 0.06e. 1.16f. 0g. 5/3h. √2

nikitadnepr [17]

Answer:

c,-0.45 ,

e. 1.16

g. 5/3

h. √2

Cannot be probability.

Step-by-step explanation:

Probability of any occurrence is always in the interval of 0 to 1. 0 and 1 inclusive.

0≤P(A)≤1

Any value outside this boundaries cannot be probability.

Therefore, -0.45,1.16,5/3 and √2 cannot be probability.

4 0

3 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

What two decimals is 79 beetween

ivolga24 [154]

Answer:

79

Step-by-step explanation:

so you dont move anything,

7 0

2 years ago

Read 2 more answers

Benjamin writes an expression for the sum of 1 cubed, 2 cubed, and 3 cubed -- What is the value of the expression? options---

saw5 [17]

Answer:

36

Step-by-step explanation:

1^3 + 2^3 + 3^3= 1+8+27

9+27= 36

7 0

3 years ago