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3 years ago

Sum1 help plzzzzzzzzzz

Mathematics

2 answers:

Sunny_sXe [5.5K]3 years ago

7 0

6.
4th, 6th, 7th, 10th, 11th, and 13th

Yuri [45]3 years ago

3 0

Answer:

The picture is a little blurry but I believe 6 of them include 2 true answers and 2 false answers

Step-by-step explanation:

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What is the formula to find the area of a circle?

VMariaS [17]

Answer:it’s A

Step-by-step explanation:

5 0

3 years ago

B. Using your answer in letter a or write the equation of the line in the form Ax + By = C

Svetradugi [14.3K]

Answer:

Step-by-step explanation:

(1, 5.5) ; (2, 9)

Slope = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\$

$= \frac{9-5.5}{2-1}\\\\=\frac{3.5}{1}\\\\= 3.5$

= 7/2

m = 7/2 ; (2 , 9)

y - y1 =m(x -x1)

$y - 9 = \frac{7}{2}(x- 2)\\\\y - 9 = \frac{7}{2}x - \frac{7}{2}*2\\\\y -9 = \frac{7}{2}x - 7\\\\y = \frac{7}{2}x - 7 + 9\\\\y = \frac{7}{2}x + 2$

Multiply the equation by 2

$2y = 2*\frac{7}{2}x + 2 *2\\\\2y = 7x + 4\\\\7x - 2y = -4\\$

4 0

3 years ago

Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^

Gemiola [76]

Answer:

$\rm \displaystyle y' = 2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x}$

Step-by-step explanation:

we would like to figure out the differential coefficient of $e^{2x}(1+\ln(x))$

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

$\displaystyle y = {e}^{2x} \cdot (1 + \ln(x) )$

to do so distribute:

$\displaystyle y = {e}^{2x} + \ln(x) \cdot {e}^{2x}$

take derivative in both sides which yields:

$\displaystyle y' = \frac{d}{dx} ( {e}^{2x} + \ln(x) \cdot {e}^{2x} )$

by sum derivation rule we acquire:

$\rm \displaystyle y' = \frac{d}{dx} {e}^{2x} + \frac{d}{dx} \ln(x) \cdot {e}^{2x}$

Part-A: differentiating $e^{2x}$

$\displaystyle \frac{d}{dx} {e}^{2x}$

the rule of composite function derivation is given by:

$\rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dg} f(g(x)) \times \frac{d}{dx} g(x)$

so let g(x) [2x] be u and transform it:

$\displaystyle \frac{d}{du} {e}^{u} \cdot \frac{d}{dx} 2x$

differentiate:

$\displaystyle {e}^{u} \cdot 2$

substitute back:

$\displaystyle \boxed{2{e}^{2x} }$

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

$\displaystyle \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)$

let

$f(x) \implies \ln(x)$
$g(x) \implies {e}^{2x}$

substitute

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \frac{d}{dx}( \ln(x) ) {e}^{2x} + \ln(x) \frac{d}{dx} {e}^{2x}$

differentiate:

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \boxed{\frac{1}{x} {e}^{2x} + 2\ln(x) {e}^{2x} }$

Final part:

substitute what we got:

$\rm \displaystyle y' = \boxed{2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} }$

and we're done!

6 0

3 years ago

The graph shows y in direct variation with x. Find the value of Y when X=-15

telo118 [61]

Y = 2x
y = 2*(-15) = -30 . . . . . selection A is appropriate

6 0

3 years ago

Write an<br> equation of the circle with center (-4,5) and radius 8.

Verizon [17]

Answer:

(x+4)2+(y-5)2=8

6 0

3 years ago