Answer:
2 sqrt(5) =x
Step-by-step explanation:
We can use the Pythagorean theorem since this is a right triangle
a^2 + b^2 = c^2
2^2 +4^2 = x^2
4+16 = x^2
20 = x^2
Take the square root of each side
sqrt(20) = sqrt(x^2)
sqrt(4*5) = x
sqrt(4) sqrt(5) =x
2 sqrt(5) =x
Radius, r = 3
The equation of a sphere entered at the origin in cartesian coordinates is
x^2 + y^2 + z^2 = r^2
That in spherical coordinates is:
x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)
where you can make u = r cos(phi) to obtain the parametrical equations
x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u
where theta goes from 0 to 2π and u goes from -r to r.
In our case r = 3, so the parametrical equations are:
Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
Answer:
(-2, 4.111)
(-1, 4.333...)
(0,5)
(1, 7)
Step-by-step explanation:
So for this, you just substitute x with a cero to obtain the x-axis.
So, (0,5)
Then, you do the same with other numbers (replace x) and get the points to later graph it.
Also, you can use desmos, it really helps
