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levacccp [35]
3 years ago
10

(10x2 + 99x – 5) ÷ (x + 10) =

Mathematics
1 answer:
Rasek [7]3 years ago
5 0

The answer to this problem is 10x - 1 with a 5 reminder, which can also be written as 10x - 1 + 5/(x + 10).

To find this, we first have to turn it into a long division problem. First we look to see how many times x goes into 10x^2.

10x^2/x = 10x.

Now we eliminate the first term and multiply the 10x by the second term.

10x * 10 = 100x.

We now subtract that 100x from 99x. This gives us a -x remainder. We can now see how many times x goes into that as well.

-x/x = -1

This gives us the final answer of 10x - 1 with a 5 remainder.

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A spherical block of ice melts so that its surface area decreases at a constant rate: ds/dt = - 8 pi cm^2/s. calculate how fast
sveticcg [70]
The rate a which the surface area, S, decreases is
\frac{dS}{dt} =-8 \pi \, cm^{2}/s

The surface area is
S = 4πr²
where r =  the radius at time t.

Therefore
\frac{dS}{dt} = \frac{dS}{dr}  \frac{dr}{dt} =8 \pi r  \frac{dr}{dt} \\\\ -8 \pi  = 8 \pi r  \frac{dr}{dt} \\\\  \frac{dr}{dt} =- \frac{1}{r}

When r = 3 cm, obtain
\frac{dr}{dt}]_{r=3} = - \frac{1}{3} \, cm/s

Answer:  -1/3  cm/s  (or -0.333 cm/s)
5 0
3 years ago
Please help me will give a lot of points.
8090 [49]
It’s b becuse if u multiple it’s is b
3 0
2 years ago
Enter the difference between the rates of change for these two functions.
Alchen [17]

Answer:

.

Step-by-step explanation:

Graph :

Choose any two points. (0 , 2) and (-1 , -2)

Rate of change = Change in y ÷ Change in x

                          = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=  \frac{-2 - 2}{-1 - 0}\\\\=  \frac{-4}{-1}\\\\= 4

Table:

Rate of change = \frac{-2-[-6]}{2-0}

                          =  \frac{-2+6}{2}\\\\=  \frac{4}{2}\\\\= 2

4 0
2 years ago
You are situated 300 feet from the base of Tower Glitz Plaza watching an external elevator descend down the side of the building
nordsb [41]

Answer:

18.66 ft/s

Step-by-step explanation:

The distance between you and the elevator is given by:

h=\sqrt{x^2+y^2}

The rate of change for the distance between you and the elevator is given by:

\frac{dh}{dt}=\frac{dh}{dy}*\frac{dy}{dt}

-16=\frac{dh}{dy}*\frac{dy}{dt}

\frac{dh}{dy}=\frac{d}{dy} (\sqrt{x^2+y^2})\\

Applying the chain rule:

u=x^2+y^2\\\frac{dh}{dy}=\frac{d\sqrt u}{du} *\frac{du}{dy}\\\frac{dh}{dy}=\frac{1}{2\sqrt u} *2y\\\frac{dh}{dy}=\frac{y}{\sqrt {(x^2+y^2)}}

Therefore, at x=300 and y = 500, dy/dt is:

-16=\frac{y}{\sqrt {(x^2+y^2)}}*\frac{dy}{dt}\\-16=\frac{500}{\sqrt {(300^2+500^2)}}*\frac{dy}{dt}\\\frac{dy}{dt}=-18.66\ ft/s

The elevator is descending at 18.66 ft/s.

7 0
3 years ago
What is the area of the shaded portion in the parallelogram below?<br>​
tensa zangetsu [6.8K]

Answer:

Area of trapeze= (B+b):2×h

Therefore : (7+10):2×4=34

Good luck!

5 0
3 years ago
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