Answer:
<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will help uh</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
The mean is also increased by the constant k.
Step-by-step explanation:
Suppose that we have the set of N elements
{x₁, x₂, x₃, ..., xₙ}
The mean of this set is:
M = (x₁ + x₂ + x₃ + ... + xₙ)/N
Now if we increase each element of our set by a constant K, then our new set is:
{ (x₁ + k), (x₂ + k), ..., (xₙ + k)}
The mean of this set is:
M' = ( (x₁ + k) + (x₂ + k) + ... + (xₙ + k))/N
M' = (x₁ + x₂ + ... + xₙ + N*k)/N
We can rewrite this as:
M' = (x₁ + x₂ + ... + xₙ)/N + (k*N)/N
and (x₁ + x₂ + ... + xₙ)/N was the original mean, then:
M' = M + (k*N)/N
M' = M + k
Then if we increase all the elements by a constant k, the mean is also increased by the same constant k.
Answer:
um i can't really understand what your trying to do here
Step-by-step explanation:
Solutions
Factor <span>3x</span>²<span><span>−2x−8</span><span>
</span></span>1. Multiply 3 by -8, which is -24.
2. Ask: Which two numbers add up to -2 and multiply to -24?
3. Answer: 4 and -6
4. Rewrite <span>−2x </span>as the sum of <span>4x </span>and <span>−6x</span>:

<span>
</span><span>Factor out common terms in the first two terms, then in the last two terms
</span>
Factor out the common term <span>3x+4
</span>
Solve for <span>x
</span>1. Ask: When will <span>(3x+4)(x−2) </span>equal zero?
2. Answer: When <span>3x+4=0 </span>or <span>x−2=0.</span>
3. Solve each of the 2 equations above:
x = −<span>4 / 3</span>,<span>2</span>