Answer:
clc%clears screen
clear all%clears history
close all%closes all files
p=250;
M=[];
for i=1:100000
re=0;
S=0;
while(S<=1)
S=S+rand;
re=re+100;
end
M(i)=re;
end
disp('Expected received money is');
mean(M)
disp('Since expcted is greater than what we pay. So, we will play')
Step-by-step explanation:
If the sample size is 1488 and confidence interval of 99% then the margin of error is 0.03088.
Given sample size of 1488, percentage of those polled own a home be 69% and confidence level be 99%.
We are required to find the approximate margin of error.
Margin of error is the difference between calculated values and real values.
n=1488
p=0.69
Margin of error=z*
Z score when confidence level is 99%=2.576.
Margin of error=2.576*
=2.576*
=2.576*
=2.576*
=2.576*0.01198
=0.03088
Hence if the sample size is 1488 and confidence interval of 99% then the margin of error is 0.03088.
Learn more about margin of error at brainly.com/question/10218601
#SPJ1