Answer:
D. The point at x = 0 is x-intercept itself.
Step-by-step explanation:
First, substitute x = 0 in f(x) = sin(x) and examine the point and values.
When x = 0, sin(0) = 0.
Hence, the point is (0,0) which is an origin point. It is both x-intercept and y-intercept at the same time.
The point at x = 0 is neither maximum nor minimum since the range of some function is defined in [-1,1] so the minimum value has to be -1 and the maximum value has to be 1.
Thus, A and B are not correct choices.
The C choice would make sense if the value of f(x) did not become 0 when substituting x = 0 in.
Therefore, the correct choice is D as it is an origin point at x = 0 meaning it is both x-intercept and y-intercept.
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Answer:
No solution
Step-by-step explanation:
3x + 5 - x = 2(x-1)-4
2x + 5 = 2x - 2 - 4 Add the like terms. Distribute the 2.
2x = 2x - 6 - 5 Subtract 5, add like terms
2x = 2x - 11 Add like terms
0 ≠ -11 Subtract 2x to keep variables on one side
Since zero does not equal -11, there are no solutions
Answer:
its B. 3
^-^
Step-by-step explanation:
4(2)^4 - 2(7^2) + 40
4(16)-2(49)+40
64 - 98 + 40
-34 + 40
= 6