<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
</span>
<span>I hope this helps! </span>
<h2>6 is the answer.</h2>
just simple
<span>Maybe xy is also given ........................</span>
Answer: 2, 2, 2, 5, 13, 13.
Step-by-step explanation:
Here is the math in order to find the prime factorization
6760 ÷ 2 = 3380
3380 ÷ 2 = 1690
1690 ÷ 2 = 845
845 ÷ 5 = 169
169 ÷ 13 = 13
13 ÷ 13 = 1
