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3 years ago

rename 1/2 and 2/3 as fractions with denominators of 6.then add the renamed fractions. write the sum as a mixed number.

Mathematics

1 answer:

monitta3 years ago

4 0

Answer:

1 and 1/6

Step-by-step explanation:

To rename a fraction you multiply both numbers by however many times the original denominator goes into the new one.

2 goes into 6 three times.

1 times 3 is 3

and 2 times 3 is 6

so 1/2=3/6

3 goes into 6 twice

2 times 2 is 4

and 2 times 3 is 6

so 2/3=4/6

to add fractions you add the numerators while keeping the denominators the same.

3+4=7 so:

3/6+4/6=7/6

6/6=1

so 7/6 contains 1 whole

once you take that out you have 1/6 left over

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5x−4 = 3x +8 i need the steps on how to find x plz, i got a 0 the first time i did it

svetoff [14.1K]

Answer:

5x − 4 = 3x + 8

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5x - 3x = 3x + 12 - 3x

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Brut [27]

Step-by-step explanation:

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3 years ago

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In addition, what is the inverse

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2 years ago

The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly

Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between $\\ (\mu - 6\sigma)$ and $\\ (\mu + 6\sigma)$ . It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

$\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027$

For those with defects operating at a 6 sigma level, the probability is:

$\\ 1 - p = 1 - 0.999999998027 = 0.000000001973$

Similarly, for finding no defects in a 5 sigma level, we have:

$\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697$ .

The probability of defects is:

$\\ 1 - p = 1 - 0.999999426697 = 0.000000573303$

Well, the defects present in a six sigma level and a five sigma level are, respectively:

$\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}$

$\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}$

Then, comparing both fractions, we can confirm that a 6 sigma level is markedly different when it comes to the number of defects present:

$\\ {6\sigma} \approx \frac{2}{10^9}$ [1]

$\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9}$ [2]

Comparing [1] and [2], a six sigma process has 2 defects per billion opportunities, whereas a five sigma process has 600 defects per billion opportunities.

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2 years ago

Find the first term of the sequence 4, 12, 36, 108.... which exceeds 20,000.

Schach [20]

Answer:

43740

Step-by-step explanation:

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2 years ago