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larisa [96]
4 years ago
10

Find the range of the function for the fiven domain. f(x)= 3x-8; {-2, -1, 0, 1, 2}

Mathematics
1 answer:
ryzh [129]4 years ago
7 0
<span>f(x)= 3x-8

x = -2,  </span><span>f(x)= 3(-2) -8 = -6 - 8 = -14
</span>x = -1,  f(x)= 3(-1) -8 = -3 - 8 = -11
x = 0,  f(x)= 3(0) -8 = 0 - 8 = -8
x = 1,  f(x)= 3(1) -8 = 3 - 8 = -5
x = 2,  f(x)= 3(2) -8 = 6 - 8 = -2
Domain <span> {-2, -1, 0, 1, 2}
</span>Range: <span> {-14, -11, -8, -5, -2}
</span>
answer
Range:  {-14, -11, -8, -5, -2}
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Step-by-step explanation:

Let's take the coordinates of point A for the set of reflections and rotations given in the options.

Option (1). Rotate 180° → A(-4, 1) becomes (4, -1)

                Reflect over x-axis → (4, -1) becomes (4, 1)

                Reflect over the line y = x → (4, 1) becomes A'(1, 4)

Therefore, point A will not overlap itself after the number of transformations given.

Option (2). Reflect across x-axis → A(-4, 1) will become (-4, -1)

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                  Reflect over the x-axis → (4, 1) becomes A'(4, -1)

Therefore, point A(-4, 1) doesn't overlap A'(4, -1).

Option (3). Rotate 180° → A(4, 1) becomes (-4, -1)

                  Reflect over the y-axis → (-4, -1) becomes (4, -1)

                  Reflected over y = x → (4, -1) becomes (-1, 4)

So the point A(4, 1) becomes A'(-1, 4) after the set of reflections,

Option (4). Reflect over the y axis → A(-4, 1) becomes (4, 1)

                 Reflect over the x-axis → (4, 1) becomes (4, -1)

                 Rotate 180° → (4, -1) becomes A'(-4, 1)

Therefore, point A will overlap itself following the set of transformations.

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4 years ago
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