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Yuri [45]
3 years ago
10

The area of a rectangle is 8w + 18 square feet. The length of the rectangle is 2 feet. Use factoring to write an expression to r

epresent the width of the rectangle.
Mathematics
1 answer:
qwelly [4]3 years ago
6 0

Answer:

4w + 9

Step-by-step explanation:

Area of rectangle = length x width (or base x height, depending on how you look at it).

It is given to you that:

Area = 8w + 18

Length = 2

Let: width = x

Plug in the corresponding terms with the corresponding words:

8w + 18 = 2x

Isolate the variable, x. Divide 2 from both sides of the equation:

(8w + 18)/2 = (2x)/2

x = (8w + 18)/2

w = (8w)/2 + (18)/2

w = 4w + 9

4w + 9 is the expression that represents the width of the rectangle.

~

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3(x-6)^4+11=15 solve for x
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Answer:

x = 7.07 or 4.925

Step-by-step explanation:

3(x-6)^4+11=15

3(x-6)^4=15-11

(x-6)^4=4/3

x-6 = +\sqrt[4]{4/3} or -\sqrt[4]{4/3}

x= +\sqrt[4]{4/3} +6 or -\sqrt[4]{4/3}  +6

x = 7.07 or 4.925

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2 years ago
The average of a list of 4 numbers is 90.0. A new list of 4 numbers has the same first 3 numbers as the original list, but the f
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Answer:

the average of this new list of numbers is 94

Step-by-step explanation:

Hello!

To answer this question we will assign a letter to each number for the first list and the second list of numbers, remembering that the last number of the first list is 80 and the last number of the second list is 96

for the first list

\frac{a+b+c+80}{4} =90

for the new list

\frac{a+b+c+96}{4} =X

To solve this problem consider the following

1.X is the average value of the second list

2. We will assign a Y value to the sum of the numbers a, b, c.

a + b + c = Y to create two new equations

for the first list

\frac{y+80}{4} =90

solving  for Y

Y=(90)(4)-80=280

Y=280=a+b+c

for the second list

\frac{y+96}{4} =X\\

\frac{280+96}{4} =X\\x=94

the average of this new list of numbers is 94

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3 years ago
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