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GREYUIT [131]
3 years ago
8

Plz answer immediately

Mathematics
1 answer:
makkiz [27]3 years ago
6 0

1 2/3 because 3 * 5/3 = 5 and 1 2/3 = 5/3

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At Jefferson Middle School, eighty-two students were asked which sports they plan to participate in for the coming year. Twenty
blondinia [14]

Answer:

30 students they are including the students that are also planning to participate in other sports to.

8 0
3 years ago
Determine the type and number of solutions of −4x2 − 3x + 7 = 0.
Kaylis [27]

Answer:

Step-by-step explanation:

You have to use the discriminant for this. If the quadratic is -4x^2-3x+7, then

a = -4, b = -3, and c = 7. The formula for finding the discriminant is

D=b^2-4ac which comes from the quadratic formula, but without the square root sign. Filling in:

D=(-3)^2-4(-4)(7) which simplifies down to

D = 9 + 112 so

D = 121. This is a perfect square, so the solutions will be 2 real. Just so you know, you will NEVER have a solution like the one offered in the third choice down. If you have one imaginary root, you will ALWAYS have a second by the conjugate rule.

7 0
3 years ago
You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water you
NARA [144]

Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) =  -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

And the height is in feet, then the maximum height is 12.5626 ft

6 0
3 years ago
The question is in the picture
yawa3891 [41]

Answer: May you show the angle we are supposed to solve? its a bit unclear. or can you explain the angle to us?

Step-by-step explanation:

6 0
3 years ago
Geometry homework help???
tatuchka [14]
The explorer's running velocity will be 1/3 the velocity of the train, 45/3 = 15. From those issue statement, the train will a chance to be at the begin of the span The point when those voyagers have run 1/3 of the period of the span. In they run of the much end of the bridge, they will bring run 1/3 of the length of the span when those prepare achieves the close to wind. Beginning starting with those 1/3 point, they will make toward those 2/3 perspective At those prepare achieves those span. The prepare will travel the full period of the span in the the long haul it takes those voyagers to run those remaining 1/3. Accordingly the train must travel toward three times the running speed of the voyager. Train = 45 mph, voyagers = 15 mph. The speed of P&D = 15 mph
3 0
3 years ago
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