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Lady bird [3.3K]

3 years ago

7

ILL MARK YOU BRAINLIEST PLEASEEEEEEEW HELPPPPSJSOSJSB compare the expressions 7+3^2- 2•5 and (3/4+1/8) divided by 1/8 using <

,= or > show your work

1 answer:

Alona [7]3 years ago

3 0

No me han dicho que me ha dicho nada de la policía y que han

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Multiply. PLZ HLEP I AM CONFUSED <br><br><br>3√⋅2√2⋅58√⋅√18

Sloan [31]

Answer: 120√6

*I apologize for the late response, if any of you need this, I'm happy to help. If the explanation isn't clear, please message me and we can work from there. I have checked this answer 3 times and it has been correct all those three times.*

Question and procedure:

√3 x 2√2 x 5√8 x √18

To solve, first, you should simplify any roots that need simplifying.

The two roots that need simplifying are 5√8 and√18.

In 5√8, you can still simplify the √8, there are four factors of 8: 1,2,4,8. The only two factors that you will be able to further simplify are 2 and 4.

TO SOLVE:

√2 x √4 = 2√2

then, you multiply 2√2 x 5, getting you 10√2

( the root of 4 is 2)

THE OTHER ROOT:

√18: 18 has the following factors: 1,2,3,6,9,18. The two factors that you will be able to further simplify are 9 and 2.

So, √18 is 3√2.

Now we can solve the problem:

√3 x 2√2 x 10√2 x 3√2

( <em>when solving, it is important to keep in mind that you are supposed to multiply the number OUTSIDE the root together and the numbers INSIDE of the root together) </em>

√3 x 2√2 = 2√6.

2√6 x 10√2 = 20 √12

* WE ARE ABLE TO SIMPLIFY 20√12 into 40√3.

40√3 x 3√2 = 120√6.

8 0

3 years ago

Read 2 more answers

Name the set or sets of numbers to which each real numbers belong. Please help me firgure this out or any answers!?

Anon25 [30]

I am following this post

6 0

3 years ago

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The height h (in feet) of an object dropped from a ledge after x seconds can be modeled by h(x)=−16x2+36 . The object is dropped

kakasveta [241]

Check the picture below.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}$

so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?

$\bf h(x)=-16x^2+36\implies \stackrel{h(x)}{0}=-16x^2+36\implies 16x^2=36 \\\\\\ x^2=\cfrac{36}{16}\implies x^2 = \cfrac{9}{4}\implies x=\sqrt{\cfrac{9}{4}}\implies x=\cfrac{\sqrt{9}}{\sqrt{4}}\implies x = \cfrac{3}{2}~~\textit{seconds}$

now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2 = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill$

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

4 0

3 years ago

Reflection across the y-axis<br> H(4, -3), (3, 1), J5, -1)

Stells [14]

Answer:(3,1)

Step-by-step explanation:

6 0

3 years ago

Tamira has 8 pounds of clay. How many 4-ounce<br> bowls can she make with the clay?

Jobisdone [24]

Answer:

32

Step-by-step explanation:

8 pounds = 128 ounces

128 ÷ 4 = 32

4 0

3 years ago

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