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ozzi
3 years ago
9

Write 1/4, 1/2, and 3/4 as decimals. *

Mathematics
2 answers:
mash [69]3 years ago
8 0
.25, .50, .75 for the decimals
zimovet [89]3 years ago
3 0

Answer:

.25, .5 and .75

Step-by-step explanation:

1 \div 4

punch that into a calculator it say .25

1 \div 2

punch that into a calculator it says .5

3 \div 4

punch that into a calculator it says .75

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The diagram shows parallel lines cut by two transversal lines creating a triangle. Which statement can be made from the diagram?
yaroslaw [1]

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Step-by-step explanation: got it right on edge

4 0
2 years ago
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Why does it take 3 copies of 1/6 to show the same amount as 1 cooy of 1/2
aleksandrvk [35]
Because 1/2 = 3/6
therefore you have to multiply 1/6 by 3 to achieve that.
4 0
3 years ago
Use the general slicing method to find the volume of the following solids. The solid whose base is the region bounded by the cur
Y_Kistochka [10]

Answer:

The volume is V=\frac{64}{15}

Step-by-step explanation:

The General Slicing Method is given by

<em>Suppose a solid object extends from x = a to x = b and the cross section of the solid perpendicular to the x-axis has an area given by a function A that is integrable on [a, b]. The volume of the solid is</em>

V=\int\limits^b_a {A(x)} \, dx

Because a typical cross section perpendicular to the x-axis is a square disk (according with the graph below), the area of a cross section is

The key observation is that the width is the distance between the upper bounding curve y = 2 - x^2 and the lower bounding curve y = x^2

The width of each square is given by

w=(2-x^2)-x^2=2-2x^2

This means that the area of the square cross section at the point x is

A(x)=(2-2x^2)^2

The intersection points of the two bounding curves satisfy 2 - x^2=x^2, which has solutions x = ±1.

2-x^2=x^2\\-2x^2=-2\\\frac{-2x^2}{-2}=\frac{-2}{-2}\\x^2=1\\\\x=\sqrt{1},\:x=-\sqrt{1}

Therefore, the cross sections lie between x = -1 and x = 1. Integrating the cross-sectional areas, the volume of the solid is

V=\int\limits^{1}_{-1} {(2-2x^2)^2} \, dx\\\\V=\int _{-1}^14-8x^2+4x^4dx\\\\V=\int _{-1}^14dx-\int _{-1}^18x^2dx+\int _{-1}^14x^4dx\\\\V=\left[4x\right]^1_{-1}-8\left[\frac{x^3}{3}\right]^1_{-1}+4\left[\frac{x^5}{5}\right]^1_{-1}\\\\V=8-\frac{16}{3}+\frac{8}{5}\\\\V=\frac{64}{15}

5 0
3 years ago
A sample from a group of people will not always be representative of the entire group.
worty [1.4K]
True of False? It depends on the scenario of the data size.
3 0
3 years ago
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Can u guys PLEASE answer the depreciation question ASAP. THIS IS URGENT!
Furkat [3]

Answer: the value of the car after 7 years is $11220

Step-by-step explanation:

The formula for determining depreciation is expressed as

A = P(1 - r)^t

Where

A represents the final value of the car after t years.

P represents the present value of the car.

r represents the rate of depreciation

t represents the number of years.

From the information given

P = 35000

r = 15% = 15/100 = 0.15

t = 7 years

Therefore,

A = 35000(1 - 0.15)^7

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A = 11220.198

Rounding up yo the nearest dollar, it becomes $11220

8 0
3 years ago
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