When a point divide a line segment A (x1,y1) B (x2,y2) into a ration of a:b, the coordinates of that point is x1+[a/(a+b)](x2-x1), y1+[a/(a+b)](y2-y1)
so x=0+(2/3)(6-0)=4
y=4+(2/3)(8-4)=6&2/3 (mixed number 6 and 2 over 3)
(4, 6&2/3) is the answer.
X = 0
I hope this helps you in some way. :)
The answer is 5x^2-x because you have to plug in and then distribute.
We know that
in a quadratic equation of the form
ax²+bx+c=0
the discriminant is
D=b²-4ac
if D> 0 <span>then there are two real number solutions
if D=0 </span><span>then there's only one real number solution.
if D< 0 </span><span>then there are two complex number solutions
in this problem
we have
</span>3x²<span>-6x+3=0
a=3
b=-6
c=3
so
</span>D=b²-4ac-----> D=(-6)²-4*(3*3)----->D=36-36------->D=0
therefore
there's only one real number solution
Answer:
In mathematics and computer science, a recursive definition, or inductive definition, is used to define the elements in a set in terms of other elements in the set. Some examples of recursively-definable objects include factorials, natural numbers, Fibonacci numbers, and the Cantor ternary set.
Step-by-step explanation:
