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dybincka [34]
3 years ago
12

Item 12 What is the shape of the cross section of the cylinder in each situation? Drag and drop the answer into the box to match

each situation. Cylinder is sliced so the cross section is parallel to the base. Cylinder is sliced so the cross section is perpendicular to the base.

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
7 0

Answer:circle/rectangle

Step-by-step explanation: cylinder is sliced so the cross section is parallel to the base = circle

cylinder is sliced so the cross section is perpendicular to the base=rectangle

Goryan [66]3 years ago
5 0

You can build a cylinder in two ways: either you draw a circle on a plane, and "raise" it perpendicularly to the plane itself, or you start with a rectangle, and rotate it around one of its sides.

For these reasons, if you cut the cylinder with a plane parallel to the base you have a circular cross section, while if you cut the cylinder with a plane perpendicular to the base you have a rectangular cross section.

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Answer:

k = 3

Step-by-step explanation:

We have the distance formula: d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}. We can plug in 4\sqrt{2} = d, x2 = 6, x1=2, y2 = 7, y1 = k.

Then, we can solve the question using some algebra to find that k = 3.

Edit: Here is a step by step:

4\sqrt{2} = \sqrt{(6-2)^2 + (7-k)^2}\\

(4\sqrt{2})^2 = (6-2)^2 + (7-k)^2

32 = (4)^2 + (7-k)^2

32 = 16 + (7-k)^2

32 - 16 =  (7-k)^2

16 =  (7-k)^2

\sqrt{16} =  (7-k)

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k = 3

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The following scatter plot shows the number of page views for a popular website and how many people signed up to receive emails
My name is Ann [436]

Answer:

See Explanation.

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

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  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Algebra I</u>

Slope Formula: \displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Slope-Intercept Form: y = mx + b

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Linear Regression

Step-by-step explanation:

We can draw any best line of fit, as long as it is <em>reasonable</em> around the points that are given.

We can just take 2 points and use slope formula and Slope-Intercept Form to find the equation for the best line of fit.

Using Linear Regression, we can determine the <em>true</em> best line of fit using graphing utilities.

<u>Finding the best line of fit</u>

<em>Define 2 points</em>

Point (21600, 205)

Point (27000, 290)

<em>Find slope m</em>

  1. Substitute in point [SF]:                    \displaystyle m=\frac{290-205}{27000-21600}
  2. [Fraction] Subtract:                           \displaystyle m=\frac{85}{5400}
  3. [Fraction] Simplify:                            \displaystyle m=\frac{17}{1080}

<em>Find equation</em>

  1. Define equation [SIF]:                        \displaystyle y = \frac{17}{1080}x + b
  2. Substitute in point:                            \displaystyle 290 = \frac{17}{1080}(27000) + b
  3. Multiply:                                             \displaystyle 290 = 425 + b
  4. Isolate y-intercept <em>b</em>:                         \displaystyle -135 = b
  5. Rewrite:                                             \displaystyle b = -135
  6. Redefine equation:                           \displaystyle y = \frac{17}{1080}x - 135

Slope-Intercept Form tells us that our slope <em>m</em> = \displaystyle \frac{17}{1080} and our y-intercept \displaystyle b = -135.

Setting this as function f(x), we can see from the graph that it is extremely accurate (Blue line).

<u>Using Linear Regression</u>

Depending on the graphing calc you have, the steps may be different.

Using a graphing calc, we can use statistics and determine the <em>best</em> best line of fit.

When we determine the values, we should see that our equation would be g(x) (Green Line).

<em>Credit to Lauren for collabing w/ me in graphing.</em>

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