1/6 divided by 2
Keep, change, flip
1/6 * 1/2 = 1/12
Answer: 1/12
What are the ratios and what are the different bins
If length is x, then width is 6+x
<span>Perimeter = 2*(x + 6+x) = 52 </span>
<span>2*6 + 2*2x = 52 </span>
<span>4x = 52 - 12 = 40 </span>
<span>x = 40/4 = 10 </span>
<span>Area = length*width = 10*(6+10) </span>
<span>Area = 10*16 = 160 meter square</span>
Answer:
The correct answer is option C
(f o g)(x) = 3x² + 7x + 2
Step-by-step explanation:
<u>Points to remember</u>
<u>Composite functions</u>
Let f(x) and g(x) be the two functions then (f o g)(x) can be written as
(f o g)(x) = f(g(x))
<u>To find the value of (f o g)(x)</u>
Here f(x) =x + 2 and g(x) = 3x² + 7x
(f o g)(x) = f(g(x))
= f(3x² + 7x)
= 3x² + 7x + 2
Therefore the correct answer is option C
(f o g)(x) = 3x² + 7x + 2
The first step is to determine the distance between the points, (1,1) and (7,9)
We would find this distance by applying the formula shown below
![\begin{gathered} \text{Distance = }\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ \text{From the graph, } \\ x1\text{ = 1, y1 = 1} \\ x2\text{ = 7, y2 = 9} \\ \text{Distance = }\sqrt[]{(7-1)^2+(9-1)^2} \\ \text{Distance = }\sqrt[]{6^2+8^2}\text{ = }\sqrt[]{100} \\ \text{Distance = 10} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%7D%20%5C%5C%20%5Ctext%7BFrom%20the%20graph%2C%20%7D%20%5C%5C%20x1%5Ctext%7B%20%3D%201%2C%20y1%20%3D%201%7D%20%5C%5C%20x2%5Ctext%7B%20%3D%207%2C%20y2%20%3D%209%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B%287-1%29%5E2%2B%289-1%29%5E2%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B6%5E2%2B8%5E2%7D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B100%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%2010%7D%20%5Cend%7Bgathered%7D)
Distance = 10 units
If one unit is 70 meters, then the distance between both entrances is
70 * 10 = 700 meters
